Question

我对编程非常陌生，至少面向对象所以请温柔：）

我正在尝试创建预算程序，但我无法识别字符串。我有一个名为payperiod的变量，很简单，它将用于保存每周，每月等字符串值。我在这里做错了什么？

#!/usr/bin/env ruby
#
# Simple Budgeting Program
#


puts "Hi, I would like to develop a budgeting program for you..\n\n\n\n\n"
puts "What is your budget type? \n \n \n You can say 'Monthly' 'Weekly' or 'Fortnightly'  \n"
payperiod = gets

if payperiod == "Monthly"
  puts "You are paid monthly."
end

if payperiod == "Weekly"
  puts "You are paid Weekly"
end

if payperiod == "Fortnightly"
  puts "You are paid every two weeks!"
end

Answer 1

您忘记了按下提交答案的返回键：

2.1.0 :001 > mystring = gets
Monthly
 => "Monthly\n" 
2.1.0 :002 > mystring.chomp
 => "Monthly" 
2.1.0 :003 > correct_string = gets.chomp
Monthly         
=> "Monthly"

Answer 2

获取方法将获得＆＃34;输入＆＃34;键盘键。这意味着特殊字符 \ n 将被添加到字符串的末尾，因为这是表示＆＃34;输入＆＃34;键盘键。

因此，当您输入单词＆＃34; Monthly＆＃34;，＆＃34; Weekly＆＃34;或＆＃34;每两周一次＆＃34;这个脚本真正捕获的是＆＃34;每月\ n＆＃34;，＆＃34;每周\ n＆＃34;或者＆＃34;每两周\ n＆＃34;。

因此，您的脚本必须使用chomp方法（由JCorcuera高配）来删除该字符。

如果你想使用chomp方法，你的脚本看起来像

payperiod = gets

if payperiod.chomp == "Monthly"
  puts "You are paid monthly."
elsif payperiod.chomp == "Weekly"
  puts "You are paid Weekly"
elsif payperiod.chomp == "Fortnightly"
  puts "You are paid every two weeks!"
else
  puts "Invalid option!"
end

如果您不想使用chomp，可以附加＆＃34; \ n＆＃34;

payperiod = gets

if payperiod == "Monthly\n"
  puts "You are paid monthly."
elsif payperiod == "Weekly\n"
  puts "You are paid Weekly"
elsif payperiod == "Fortnightly\n"
  puts "You are paid every two weeks!"
else
  puts "Invalid option!"
end

Answer 3

获取获取字符串的代表。它返回用户输入的所有内容，包括他们没有意识到它们正在放入的内容.gets.chomp删除末尾的所有空格，以便它只返回您想要的字符串。如果用户输入'每月''每月'或'十分'，那么将它包括在内也是一个好主意。

user_input：每月

mystring1 = gets
  => 'Monthly/n'
mystring2 = gets.chomp
  => 'Monthly'
mystring3 = gets.chomp.downcase
  => 'monthly'


mystring1 == 'monthly'
   => false
mystring1 == 'monthly'
   => false
mystring1 == 'monthly'
   => true

如何验证用户输入变量是否为某个字符串？

3 个答案: