Question

我有一个（工作）查询，看起来有点像：

SELECT DISTINCT
Convert(Varchar(150),O.PONumber) AS OrderID, 
CONVERT(varchar, O.OrderDateTime, 111) AS OrderDateTime, 
CONVERT(varchar, DATEADD(DAY, 14, O.OrderDateTime), 111) AS DateExpire, 
C.ClientID, 
C.ClientName, 
U.FirstName + ' ' + U.LastName AS Name
...

我想在此添加类似内容：

(SELECT 
    SUM((
        SELECT 
            OI.UnitPoints
        FROM 
            Orders O INNER JOIN
            [dbo].[OrderItems] AS OI ON O.OrderID = OI.OrderID
        WHERE 
            O.PONumber = 72084))) AS TotalPoints

由此返回的值：

SELECT 
    OI.UnitPoints
FROM 
    Orders O INNER JOIN
    [dbo].[OrderItems] AS OI ON O.OrderID = OI.OrderID
WHERE 
    O.PONumber = 72084

看起来像这样：

UnitPoits
---------
1
2

所以在这个特定的实例中，我正在寻找分配给TotalPoints的值为3（1 + 2）。

Answer 1

您可以使用GROUP BY语句来实现此目的：

SELECT 
    O.OrderID,
    SUM(OI.UnitPoints) as TotalPoints
FROM 
    Orders O INNER JOIN
    [dbo].[OrderItems] AS OI ON O.OrderID = OI.OrderID
WHERE 
    O.PONumber = 72084
GROUP BY O.OrderID

在较大的查询中选择多行的总和作为值

1 个答案: