Question

因此，Magento有一个EAV表结构，这使得编写查询非常有趣。我试图将与一个唯一客户相关的几行数据与另一个包含有关客户的其他数据的表相匹配。

为了做到这一点，我目前正在尝试在一个查询中LEFT JOIN五个表，并为每个客户构建一个结果集。

这是表结构：

客户实体表

customer_entity_varchar

+----+------------+--------------+----------+
| id | entity_id  | attribute_id |   value  |
+----+------------+--------------+----------+
|  2 | 1          | 100          | Bob Doe  |
|  3 | 1          | 101          | James    |
|  5 | 1          | 102          | Thompson |
|  7 | 2          | 100          | Bob Doe  |
|  9 | 2          | 101          | Mary     |
+----+------------+--------------+----------+

客户定价表

pricesystem_customerprice

+----+------------+--------------+----------+-------+------------+
| id | entity_id  |  customer_id |   value  |  qty  |     to     |
+----+------------+--------------+----------+-------+------------+
|  2 | 35         | 1            | 34.99    |  10   | 2014-06-18 |
|  3 | 3495       | 2            | 123.99   |  5    | 2014-06-18 |
+----+------------+--------------+----------+-------+------------+

目录产品表

catalog_product_entity

+----+------------+----------------+
| id | entity_id  |       sku      |
+----+------------+----------------+
|  2 | 35         | Fenix-E01-Blue |
|  3 | 3495       | Sunwayman-V11R |
+----+------------+----------------+

我的查询如下：

SELECT 
    t1.`value` as account_manager, 
    t2.`value` as lastname, 
    t3.`value` as firstname,
    s.sku as item,
    c.`value` as price,
    c.qty as quantity,
    c.`comment` as `comment`
FROM 
    customer_entity_varchar as t1 
        on c.customer_id = t1.entity_id AND t1.attribute_id = 286
left join 
    customer_entity_varchar as t2
        on c.customer_id = t2.entity_id AND t2.attribute_id = 5
left join
    customer_entity_varchar as t3 
        on c.customer_id = t3.entity_id AND t3.attribute_id = 7 
left join 
    pricesystem_customerprice as c 
        on c.customer_id = t2.entity_id
left join 
    catalog_product_entity as s 
        on s.entity_id = c.entity_id 
WHERE c.`to` = '2014-06-18'

语法似乎有问题，但我不太精通连接表，所以我可能输错了。我确实对此进行了一些研究，并尽可能地得到了它。

如果我不再需要获得客户的姓名，那么我可以使声明工作加入两个表。

以下是所需的结果集：

Array (
0 => array (
    account_manager => Bob Doe,
    firstname => James,
    lastname => Thompson,
    item => Fenix-E01-Blue,
    price => 34.99,
    quantity => 10),
1 => array (
    account_manager => Bob Doe,
    firstname => Mary,
    lastname => Thompson,
    item => Sunwayman-V11R,
    price => 123.99,
    quantity => 5)
)

如果您需要任何其他信息，请与我们联系。

Answer 1

您的联接稍微有点乱，您需要的是选择一个基表作为原点（这里我选择了产品表）并将所有内容加入其中;

SELECT 
    t1.`value` as account_manager, 
    t2.`value` as lastname, 
    t3.`value` as firstname,
    s.sku as item,
    c.`value` as price,
    c.qty as quantity
FROM pricesystem_customerprice as c 
LEFT JOIN customer_entity_varchar as t1 
  ON c.customer_id = t1.entity_id AND t1.attribute_id = 100
LEFT JOIN customer_entity_varchar as t2
  ON c.customer_id = t2.entity_id AND t2.attribute_id = 101
LEFT JOIN customer_entity_varchar as t3 
  ON c.customer_id = t3.entity_id AND t3.attribute_id = 102
LEFT JOIN catalog_product_entity as s 
  ON s.entity_id = c.entity_id 
WHERE c.`to` = '2014-06-18'

此外，您在每个连接上的条件应仅引用在当前连接之前已经连接的表，而不是在当前连接之下的连接中列出的表。

A simple SQLfiddle to test with

Magento MySQL查询多左连接 - 语法错误

1 个答案: