Question

我有一些麻烦让这个代码看起来整洁，因为有许多IF＆amp;需要评估的OR声明。

想法：你抛出五个骰子并挑出例如三个相同类型的1,1,1再次投掷骰子另外两个并去收集点。

棘手的是将dice1，dice2，dice3，dice4，dice5与规则集进行比较，以确定玩家得到的分数。如果dicex = 1＆amp; dicex = 1＆amp; dicex = 1＆＃34;给球员1000分？

int player1points = 0;
int player2points = 0;
Scanner in = new Scanner(System.in);
Random n1 = new Random();
int dice1 = n1.nextInt(6) + 1;
int dice2 = n1.nextInt(6) + 1;
System.out.println("Dice 1 shows " +dice1);
System.out.println("Dice 2 shows " +dice2);
System.out.println("Dice 3 shows " +dice3);
System.out.println("Dice 4 shows " +dice4);
System.out.println("Dice 5 shows " +dice5);

if /* 1+1+1+1+1 = 2000 */ (dice1==1&&dice2==1&&dice3==1&&dice4==1&&dice5==1){ 

System.out.println("You got 2000 points! Throw again?");
int points2000 = 2000;
player1points = player1points + points2000;
System.out.print("You have ");
System.out.print(player1points);
System.out.print(" points. Do you want to throw again?");
System.out.println("Yes/No?");
s = in.nextLine();
}   

else if /* 1+1+1 = 1000 */     (dice1==1&&dice2==1&&dice3==1||dice2==1&&dice3==1&&dice4==1||dice3==1&&dice4==1&&dice5==1|| dice4==1&&dice5==1&&dice1==1||dice5==1&&dice1==1&&dice2==1||dice1==1&&dice2==1&&dice4==1||d    ice2==1&&dice3==1&&dice5==1||dice3==1&&dice4==1&&dice1==1||dice4==1&&dice5==1&&dice1==1||dice1==1&&dice3==1&&dice5==1){ 
System.out.println("You got 1000 points!");
int points1000 = 1000;
player1points = player1points + points1000;
System.out.print("You have ");
System.out.print(player1points);
System.out.print(" points. Do you want to throw again?");
System.out.println("Yes/No?");
s = in.nextLine();

}

Answer 1

将roll的结果放入arrayList，然后只计算该数组列表中显示的相同数字的次数？如果有3个1，则给予1000分，否则如果有5分给出2000分。

因此，对于您的代码，您将在大多数情况下拥有相同的开头。添加方法来填充数组列表，并迭代/计算骰子滚动的结果并返回最常见的和显示的次数。

int player1points = 0;
int player2points = 0;
int count = 0;
int mostCommon = 0;
int maxCount = 0;
ArrayList<Integer> diceRolls = new ArrayList<Integer>();
Scanner in = new Scanner(System.in);
Random n1 = new Random();

//rollDice method (parameter would be number of dice to roll)

//checkResults method (count number of times each number 1-6 shows up)

if(maxCount == 3){
    player1points += 1000;
    //re-roll 2 dice if necessary
else if(maxCount == 5){
    player2points += 2000;
    //re-roll dice if wanted

这只是你可以做到的一种方式。将大块代码分解为更易于阅读的函数也是一种很好的做法，它使调试变得更容易！如果您需要帮助，请随时询问！

骰子卷组合java

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