JI在Visual Studio 2008中编写了一个.NET C#Windows窗体应用程序,当按下“开始”按钮时,该应用程序使用信号量作为线程运行多个作业。
遇到问题,表格在运行40分钟或更长时间后进入逗号。日志文件表明当前作业已完成,它从列表中选择一个新作业,然后挂起。
我注意到Windows窗体在发生这种情况时变得没有响应。表单在自己的主题中运行。
这是我正在使用的代码示例:
protected void ProcessJobsWithStatus (Status status)
{
int maxJobThreads = Convert.ToInt32(ConfigurationManager.AppSettings["MaxJobThreads"]);
Semaphore semaphore = new Semaphore(maxJobThreads, maxJobThreads); // Available=3; Capacity=3
int threadTimeOut = Convert.ToInt32(ConfigurationManager.AppSettings["ThreadSemaphoreWait"]);//in Seconds
//gets a list of jobs from a DB Query.
List<Job> jobList = jobQueue.GetJobsWithStatus(status);
//we need to create a list of threads to check if they all have stopped.
List<Thread> threadList = new List<Thread>();
if (jobList.Count > 0)
{
foreach (Job job in jobList)
{
logger.DebugFormat("Waiting green light for JobId: [{0}]", job.JobId.ToString());
if (!semaphore.WaitOne(threadTimeOut * 1000))
{
logger.ErrorFormat("Semaphore Timeout. A thread did NOT complete in time[{0} seconds]. JobId: [{1}] will start", threadTimeOut, job.JobId.ToString());
}
logger.DebugFormat("Acquired green light for JobId: [{0}]", job.JobId.ToString());
// Only N threads can get here at once
job.semaphore = semaphore;
ThreadStart threadStart = new ThreadStart(job.Process);
Thread thread = new Thread(threadStart);
thread.Name = job.JobId.ToString();
threadList.Add(thread);
thread.Start();
}
logger.Info("Waiting for all threads to complete");
//check that all threads have completed.
foreach (Thread thread in threadList)
{
logger.DebugFormat("About to join thread(jobId): {0}", thread.Name);
if (!thread.Join(threadTimeOut * 1000))
{
logger.ErrorFormat("Thread did NOT complete in time[{0} seconds]. JobId: [{1}]", threadTimeOut, thread.Name);
}
else {
logger.DebugFormat("Thread did complete in time. JobId: [{0}]", thread.Name);
}
}
}
logger.InfoFormat("Finished Processing Jobs in Queue with status [{0}]...", status);
}
//表单方法
private void button1_Click(object sender, EventArgs e)
{
buttonStop.Enabled = true;
buttonStart.Enabled = false;
ThreadStart threadStart = new ThreadStart(DoWork);
workerThread = new Thread(threadStart);
serviceStarted = true;
workerThread.Start();
}
private void DoWork()
{
EmailAlert emailAlert = new EmailAlert ();
// start an endless loop; loop will abort only when "serviceStarted" flag = false
while (serviceStarted)
{
emailAlert.ProcessJobsWithStatus(0);
// yield
if (serviceStarted)
{
Thread.Sleep(new TimeSpan(0, 0, 1));
}
}
// time to end the thread
Thread.CurrentThread.Abort();
}
// job.process()
public void Process()
{
try
{
//sets the status, DateTimeStarted, and the processId
this.UpdateStatus(Status.InProgress);
//do something
logger.Debug("Updating Status to [Completed]");
//hits, status,DateFinished
this.UpdateStatus(Status.Completed);
}
catch (Exception e)
{
logger.Error("Exception: " + e.Message);
this.UpdateStatus(Status.Error);
}
finally {
logger.Debug("Relasing semaphore");
semaphore.Release();
}
我已经尝试将我可以记录到文件中以检测问题发生的位置,但到目前为止,我还无法确定这种情况发生的位置。失去对Windows窗体的控制使我认为这与处理作业无关。有什么想法吗?
解决方案:使用RedGate ANTS进行分析产生了这个问题。直接运行时不会发生这种情况。
答案 0 :(得分:3)
我看到的第一件事就是你的Thread.CurrentThread.Abort()
电话。这是不必要的。让函数退出,线程将正常关闭。
我注意到的第二件事是,即使获取信号量发生超时,也会创建一个线程。由于线程过多,您的表单可能会挂起。
logger.DebugFormat("Waiting green light for JobId: [{0}]", job.JobId.ToString());
if (!semaphore.WaitOne(threadTimeOut * 1000))
{
logger.ErrorFormat("Semaphore Timeout. A thread did NOT complete in time[{0} seconds]. JobId: [{1}] will start", threadTimeOut, job.JobId.ToString());
// Should have exit here.
}
logger.DebugFormat("Acquired green light for JobId: [{0}]", job.JobId.ToString());
第三件事是你的工作线程正在调用一个函数,该函数只为job循环中的每个作业创建线程。如果一个作业没有完成(假设这导致一个作业被从队列中删除,因为我没有在任何地方看到那个代码。)在DoWork从睡眠状态唤醒它之前,它将迭代同一个作业并尝试创建另一个作业它的线程。