Question

我已经初始化了两个哈希映射，如下所示

Map<String,List<String>> propertiesMapList1=new HashMap<String,List<String>>();
Map<String,List<String>> propertiesMapList2=new HashMap<String,List<String>>();

并添加一个包含多个值的键。

propertiesMapList1.put(srvFld, values);
propertiesMapList2.put(srvFld, values);

我能够在两个哈希图中获取公共密钥，我如何获得相应的值？

Set<String> keysInA = new HashSet<String>(propertiesMapList1.keySet());
Set<String> keysInB = new HashSet<String>(propertiesMapList2.keySet());

// Keys in A and not in B
Set<String> inANotB = new HashSet<String>(keysInA);
inANotB.removeAll(keysInB);

// Keys common to both maps
Set<String> commonKeys = new HashSet<String>(keysInA);
commonKeys.retainAll(keysInB);

Iterator itr = commonKeys.iterator();
while(itr.hasNext()){
    System.out.println("common key ::" +itr.next());
}

Answer 1

您可以在根据其中一个密钥集创建新Set.retainAll后使用Set，然后获取两个地图的每个密钥。

Map<String,List<String>> map0 =new HashMap<String,List<String>>();
Map<String,List<String>> map1 =new HashMap<String,List<String>>();
map0.put("Foo", Arrays.asList(new String[]{"a", "b", "c"}));
map0.put("Blah", Arrays.asList(new String[]{"d", "e", "f"}));
map1.put("Baz", Arrays.asList(new String[]{"3", "4", "5"}));
map1.put("Blah", Arrays.asList(new String[]{"g", "h", "i"}));

Set<String> retained = new HashSet<String>(map0.keySet());
retained.retainAll(map1.keySet());
for (String k: retained) {
    System.out.printf("In map0: %s%n", map0.get(k));
    System.out.printf("In map1: %s%n", map1.get(k));
}

<强>输出

In map0: [d, e, f]
In map1: [g, h, i]

Answer 2

当然，它只是：

Iterator<String> itr = commonKeys.iterator();
while(itr.hasNext()){
    String key = itr.next();
    System.out.println("common key ::" + key);
    System.out.println("list1 value ::" + propertiesMapList1.get(key));
    System.out.println("list2 value ::" + propertiesMapList2.get(key));
}

想要获取公共密钥，它是两个哈希映射中的多个值

2 个答案: