Question

我一直致力于查询：业务逻辑 - 显示在指定日期范围内参加健身房的所有成员（从下拉列表中选择）。

遇到的问题 - 我意识到结果显示重复，但请你帮忙。

以下是我使用的查询。

Declare @StartDate datetime = '29 May 2014' 
Declare @EndDate datetime = '29 May 2014' 
DEclare @SiteID INT =14 

Declare @StartTime datetime = '05:00 AM' 
Declare @EndTime datetime = '10:00 PM' 
Declare @Start datetime = cast (@StartDate + ' '+ @StartTime as datetime)
Declare @End datetime = cast(@EndDate + ' ' + @EndTime as datetime )

SELECT isnull(atc.totalaccepted,0) TotalAcceptedVisits,ISNULL(att.TotalOverrideVisits, 0) AS         TotalOverrides,  isnull(att1.TotalOverrideDenieds,0) as TotalDenies, ast.Name as     VisitiedSite, c.FirstName + ' ' + c.LastName as Name, md.MemRefNo
FROM    Contacts c
inner JOIN  Attendance a on a.ContactGUID = c.GUID
inner JOIN  MemberDetail md on md.ContactGUID = c.GUID
inner JOIN  Sites ast on a.SiteID = ast.ID


OUTER APPLY 
(
SELECT  a1.contactguid,COUNT(*) totalaccepted
FROM    Attendance a1
WHERE   a1.contactguid = c.guid
AND (a1.IsSwipeSuccessful = 1)      
AND a1.accessoverridereasonid IS  NULL 
AND a1.AttendDate BETWEEN @Start AND @End
group by  a1.contactguid
)atc


outer APPLY 
(
SELECT  a2.contactguid, COUNT(*) TotalOverrideVisits
FROM    Attendance a2
WHERE   a2.contactguid = c.guid
And (a.IsSwipeSuccessful = 1)
AND a2.accessoverridereasonid IS NOT NULL 
AND a2.AttendDate BETWEEN @Start AND @End
and (a2.SiteID = @SiteID OR @SiteID = 0)
group by  a2.contactguid
) att


OUTER APPLY 
(
SELECT  a3.contactguid,COUNT(*) TotalOverrideDenieds
FROM    Attendance a3
WHERE   a3.contactguid = c.guid
AND a3.IsSwipeSuccessful = 0
AND     a3.accessoverridereasonid IS  NULL 
AND a3.AttendDate BETWEEN @Start AND @end
group by  a3.contactguid
) att1


where   (a.SiteID = @SiteID OR @SiteID = 0)
and     a.AttendDate BETWEEN @Start AND @End
order by md.MemRefNo

结果：正如您在下面看到的那样，有成员会重复自己，我只需要看到每个成员中有一行的总访问次数（如果有的话），如果有的话会覆盖，如果有则拒绝访问。

TotalAcceptedVisits TotalOverrides  TotalDenies    VisitiedSite Name           memRefNo
1                      0            0          Groblersdal  Jean T          G0030
1                      1            1          Groblersdal  Koky Bakkes     G0032
1                      0            1          Groblersdal  Koky Bakkes G0032
1                      1            1          Groblersdal  Koky Bakkes G0032
1                      0            0          Groblersdal  Naomi Fisher    G0035
1                      0            0          Groblersdal  Arthur Bart G0089
1                      0            0          Groblersdal  Tulinda Swi G0034
1                      1            0          Groblersdal  Devon Mooi  G0008
1                      1            0          Groblersdal  Devon Mooi  G0008

Answer 1

我认为你需要这样的东西：

Declare @StartDate datetime = '29 May 2014' 
Declare @EndDate datetime = '29 May 2014' 
DEclare @SiteID INT =14 

Declare @StartTime datetime = '05:00 AM' 
Declare @EndTime datetime = '10:00 PM' 
Declare @Start datetime = cast (@StartDate + ' '+ @StartTime as datetime)
Declare @End datetime = cast(@EndDate + ' ' + @EndTime as datetime )

SELECT CASE WHEN TotalAcceptedVisits > 0 THEN 1 ELSE 0 END AS TotalAcceptedVisits,
CASE WHEN TotalOverrides > 0 THEN 1 ELSE 0 END AS TotalOverrides,
CASE WHEN TotalDenies > 0 THEN 1 ELSE 0 END AS TotalDenies,
VisitiedSite, Name, MemRefNo
FROM 
    (SELECT SUM(isnull(atc.totalaccepted,0)) TotalAcceptedVisits, SUM(ISNULL(att.TotalOverrideVisits, 0)) AS         TotalOverrides,  SUM(isnull(att1.TotalOverrideDenieds,0)) as TotalDenies, ast.Name as     VisitiedSite, c.FirstName + ' ' + c.LastName as Name, md.MemRefNo
    FROM    Contacts c
    inner JOIN  Attendance a on a.ContactGUID = c.GUID
    inner JOIN  MemberDetail md on md.ContactGUID = c.GUID
    inner JOIN  Sites ast on a.SiteID = ast.ID


    OUTER APPLY 
    (
    SELECT  a1.contactguid,COUNT(*) totalaccepted
    FROM    Attendance a1
    WHERE   a1.contactguid = c.guid
    AND (a1.IsSwipeSuccessful = 1)      
    AND a1.accessoverridereasonid IS  NULL 
    AND a1.AttendDate BETWEEN @Start AND @End
    group by  a1.contactguid
    )atc


    outer APPLY 
    (
    SELECT  a2.contactguid, COUNT(*) TotalOverrideVisits
    FROM    Attendance a2
    WHERE   a2.contactguid = c.guid
    And (a.IsSwipeSuccessful = 1)
    AND a2.accessoverridereasonid IS NOT NULL 
    AND a2.AttendDate BETWEEN @Start AND @End
    and (a2.SiteID = @SiteID OR @SiteID = 0)
    group by  a2.contactguid
    ) att


    OUTER APPLY 
    (
    SELECT  a3.contactguid,COUNT(*) TotalOverrideDenieds
    FROM    Attendance a3
    WHERE   a3.contactguid = c.guid
    AND a3.IsSwipeSuccessful = 0
    AND     a3.accessoverridereasonid IS  NULL 
    AND a3.AttendDate BETWEEN @Start AND @end
    group by  a3.contactguid
    ) att1


    where   (a.SiteID = @SiteID OR @SiteID = 0)
    and     a.AttendDate BETWEEN @Start AND @End
    GROUP BY atc.totalaccepted, att.TotalOverrideVisits, att1.TotalOverrideDenieds, ast.Name, c.FirstName + ' ' + c.LastName, md.MemRefNo) TB
ORDER BY MemRefNo

因为，您不想要值的SUM，那么您可以执行上述操作，基本上将SELECT作为子查询嵌入，然后使用CASE语句查看Total Values是否大于0，如果是这样，则返回1，否则为0。

删除sql查询中的重复项

1 个答案: