Question

我已阅读this question并试图在Swift中解析AFNetworking的responseObject中的JSON，但结果总是nil。

以下摘自我的代码：

let manager = AFHTTPRequestOperationManager()

manager.requestSerializer = AFJSONRequestSerializer()
manager.responseSerializer = AFJSONResponseSerializer()
manager.requestSerializer.setAuthorizationHeaderFieldWithUsername(username, password: password)

manager.POST("endpoint-that-respond-token-in-json",
    parameters: nil,
    success: { (operation: AFHTTPRequestOperation!, responseObject: AnyObject!) in
        println(responseObject.description) // { token = "bd8f26da-219a-4a88-be80-b09207dfc067"; }

        var x: NSString = responseObject.description

        var error: NSError?
        var data = x.JSONString().dataUsingEncoding(NSUTF8StringEncoding)
        println(data) // <227b5c6e 20202020 746f6b65 6e203d20 5c226539 35613462 36642d38 6361612d 34343537 2d623937 612d3330 63613236 62316338 34315c22 3b5c6e7d 22>

        var dataString = NSString(data: data, encoding: NSUTF8StringEncoding)
        println(dataString) // "{\n    token = \"e95a4b6d-8caa-4457-b97a-30ca26b1c841\";\n}"


        var json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &error) as NSDictionary!
        println(json) // nil
    },
        failure: { (operation: AFHTTPRequestOperation!, error: NSError!) in
        println(error)
    })

N.B。

var json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: &error) as NSDictionary // without "!" I will get EXC_BAD_INSTRUCTION at run time.

Answer 1

您可以将responseObject强制转换为字典

例如

manager.POST("endpoint-that-respond-token-in-json",
parameters: nil,
success: { (operation: AFHTTPRequestOperation!, responseObject: AnyObject!) in
    println(responseObject.description) // { token = "bd8f26da-219a-4a88-be80-b09207dfc067"; }

    let responseDict = response as Dictionary<String, AnyObject>
    var token = responseDict["token"] as String!
    println(token)

},
    failure: { (operation: AFHTTPRequestOperation!, error: NSError!) in
})

P.S。从字典返回的值总是可选的

编辑：在Xcode6 beta2发布后，上面的代码不再起作用了。需要先将其强制转换为AnyObject，然后再转换为字符串

let token : String? = (responseDict["token"] as AnyObject?) as? String

无法解析AFNetworking的responseObject中的JSON

1 个答案: