我的计划目标是计算一段时间后我会有多少家商店。我提供了遵循它的程序的等式。每个商店的成本是30000美元。我开始有3家商店和他们的收入10000美元/店,所以我从我的商店获得的总金额是30000美元/月。现在,一个月后,我将能够开设新店,我的店铺将增加到4,依此类推。 7个月后,我的商店将是21,总金额必须是210000美元。你会如何修改代码来做到这一点。如果你想确保你可以用纸来计算它。我的代码中的问题是,一旦总金额达到60000或更多,程序减去30000并将计数器和商店增加1,而它必须增加计数器一次和商店两次。因为60000 $是2家商店的成本等等。
public class investmentCalculation
/** the class describe the plan of investment. Each shop costs 30000 */
{
private int income ;
private int shop ;
private int firstMoney ;
private int totalMoney1;
private int totalMoney;
//instructor
public investmentCalculation( )
{
income =10000;
shop = 3;
/** here is the cost of shop establishment */
firstMoney = 30000;
totalMoney1 = 0;
}
// here the method to achieve the goal
public int SetFor()
{ for(int i= 0; i < 7; i++)
{
totalMoney1 = totalMoney1 + totalMoney - firstMoney;
/**here is 0 = 0 + 60000 - 30000;
I got the total money from this equation
totalMoney = shop * income;
= 6 * 10000;
now the shop should be 8. However, after compiling the program the output is 7.
shop++;
totalMoney = shop * income; /** once the TotalMoney = 30000(FirstMoney) should open new shop and so on. Once the iteration reach i=7 the TotalMoney must be 210000 */
shop++;
totalMoney = shop * income;
}
System.out.println("the total money is: "+totalMoney);
return shop;}
}
/** this class to test the investmentCalculation*/
public class investmentCalculationTester
{
public static void main(String [] args)
{
investmentCalculation TT = new investmentCalculation();
int A = TT.SetFor();
System.out.println("the shops are: "+A);
}}
答案 0 :(得分:0)
试试这个。我想你应该重新计算总钱。因为店铺数是21,所以是正确的。请重新计算总金额;它永远不会是210000。
public class investmentCalculation {
private int income;
private int shop;
private int firstMoney;
private int totalMoney1;
private int shopsAdded;
public investmentCalculation() {
income = 10000;
shop = 3;
firstMoney = 30000;
totalMoney1 = 0;
shopsAdded = 0;
}
// here the method to achieve the goal
public int SetFor() {
for (int i = 0; i < 7; i++) {
totalMoney1 += income * shop;
shopsAdded = totalMoney1 / firstMoney; //Calculate how many shops can be added with the money you have.
shop += shopsAdded; //Increment the shops by the newly added shops.
totalMoney1 -= firstMoney * shopsAdded; //Decrement the cost required to form the new shops.
}
System.out.println("the total money is: " + totalMoney1);
return shop;
}
/** this class to test the investmentCalculation */
public static void main(String[] args) {
investmentCalculation TT = new investmentCalculation();
int A = TT.SetFor();
System.out.println("the shops are: " + A);
}
}`