Question

我正在构建一个Android应用程序，它使用Instagram API检索Instagram图像，然后在我的应用程序中显示它们。

我一直在尝试使用我在this上找到的唯一教程来使其工作，与this相同。

我已经能够通过在Webview中加载Instagram身份验证来实现第一部分了，但是我遇到了第二部分的问题，即通过获取Instagram imageUrl实际上从我的Instagram帐户获取图像。

具体来说，我遇到了这个部分的问题：

class LongOperation extends AsyncTask<String, Void, String> {

static String accessTokenString, id, username, urlString, imageUrlString;

@Override
protected String doInBackground(String... params) {

   try {
   URL url = new URL(tokenURLString);
   HttpsURLConnection httpsURLConnection = (HttpsURLConnection) url.openConnection();
   httpsURLConnection.setRequestMethod("POST");
   httpsURLConnection.setDoInput(true);
   httpsURLConnection.setDoOutput(true);
   OutputStreamWriter outputStreamWriter = new OutputStreamWriter(httpsURLConnection.getOutputStream());
   outputStreamWriter.write("client_id="+client_id+
                                    "client_secret="+ client_secret +
                                    "grant_type=authorization_code" +
                                    "redirect_uri="+CALLBACKURL+
                                    "code=" + token);
   outputStreamWriter.flush();

   Log.i(TAG, "before streamToString");       

   String response = streamToString(httpsURLConnection.getInputStream());

   Log.i(TAG, "after streamToString");

   JSONObject jsonObject = (JSONObject) new JSONTokener(response).nextValue();

   accessTokenString = jsonObject.getString("access_token"); //Here is your ACCESS TOKEN
   id = jsonObject.getJSONObject("user").getString("id");
   username = jsonObject.getJSONObject("user").getString("username"); 
   //This is how you can get the user info. 
   //You can explore the JSON sent by Instagram as well to know what info you got in a response
    }
    catch (Exception e)
    {
        Log.e(TAG, "ERROR AsyncTask");
    }

    return null;
    }

    //converts Stream to String
    public String streamToString(InputStream p_is)
    {
       try
       {
             BufferedReader m_br;
             StringBuffer m_outString = new StringBuffer();
             m_br = new BufferedReader(new InputStreamReader(p_is));
             String m_read = m_br.readLine();
             while(m_read != null)
             {
               m_outString.append(m_read);
               m_read =m_br.readLine();
             }

             Log.d(TAG, "m_outString: " + m_outString.toString());
            return m_outString.toString();
       }
       catch (Exception e)
       {
           Log.e(TAG, "ERROR streamToString");
       }

       return null;
    }

    @Override
    protected void onPostExecute(String result) {
    Log.d(TAG, "Executed AsyncTask");
    }

        @Override
    protected void onPreExecute() {
        Log.d(TAG, "About to execute AsyncTask");
    }

        @Override
    protected void onProgressUpdate(Void... values) {
    }
}

我想知道令牌变量是什么？（doInBackground方法，在outStreamWriter参数中）

我目前正在从AuthWebViewClient发出request_token。在我的WebView中按“授权”后，AuthWebViewClient成功从Instagram获取request_token。

但是在尝试将InputStream转换为String时出现错误！

06-16 14:14:42.302: D/tellmeaboutit(31244): About to execute AsyncTask
06-16 14:14:42.642: I/tellmeaboutit(31244): request_token: 235958nvzdj243u9o974jd1490139238
06-16 14:14:42.642: I/tellmeaboutit(31244): before streamToString
06-16 14:14:42.792: D/tellmeaboutit(31244): ERROR AsyncTask

在“streamToString之前”打印然后“ERROR AsyncTask”并且永远不会到达“在streamToString之后”。

我点击按钮启动LongOperation：

doSomethingIunno.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            new LongOperation().execute("");
        }

    });

这里有什么问题？当我尝试将InputStream转换为String时，为什么会出现错误？

Answer 1

那么，为什么不尝试使用此library而不是构建自己的代码？查看＆＃34; instagram获取Feed＆＃34;上的custom-ui示例部分。

Android Instagram API：如何检索图片

1 个答案: