我有一个包含以下示例输出的表格。
ID_Emp| Name | Date
----------------------------------
11 |Jonh |14/05/2014 8:16
11 |Jonh |14/05/2014 13:35
11 |Jonh |14/05/2014 17:23
11 |Jonh |14/05/2014 21:09
12 |Elizabe |14/05/2014 14:06
12 |Elizabe |14/05/2014 22:39
13 |Jimmy |14/05/2014 8:00
13 |Jimmy |14/05/2014 17:12
我想构建一个查询来实现以下结果：
ID_Emp|Name |Date |TimeIn |TimeOut|Hours
-------------------------------------------------------
11 |Jonh |14/05/2014 |8:16 |13:35 |5:19
11 |Jonh |14/05/2014 |17:23 |21:09 |3:46
12 |Elizabe |14/05/2014 |14:06 |22:39 |8:33
13 |Jimmy |14/05/2014 |8:00 |17:12 |9:12
答案 0 :(得分：6)
试试这个：
;with cte as
(select *, rank() over(partition by ID_Emp order by [Date]) rn
from attendance)
select src.ID_Emp, src.Name, convert(date, src.[Date]) as [Date],
concat(datepart(hour,src.[Date]),':',datepart(minute,src.[Date])) as [TimeIn],
concat(datepart(hour,tgt.[Date]),':',datepart(minute,tgt.[Date])) as [TimeOut],
concat(datediff(minute,src.[Date],tgt.[Date])/60,':',datediff(minute,src.[Date],tgt. [Date])%60) as [Hours]
from cte src
inner join cte tgt on src.ID_Emp = tgt.ID_Emp and src.rn + 1 = tgt.rn and src.rn % 2 = 1
警告：我仅在SQL Server 2008 R2上对此进行了测试，但我认为它应该适用于Oracle以及适当的修改。
说明：我们使用RANK函数按每个ID_Emp的日期和时间排序。然后，我们加入ID并获得成对行。最后，为了确保我们不选择每对连续行，我们要求源行的排名应为奇数。
答案 1 :(得分：1)
尝试此查询：
WITH Level1
AS (-- apply row numbers
SELECT ID_Emp ,
Name,
CAST(Date AS DATETIME) AS [DateTime] ,
ROW_NUMBER() OVER ( PARTITION BY ID_Emp
ORDER BY Date ) AS RowNum
FROM table1
),
LEVEL2
AS (-- find the last and next event type for each row
SELECT A.ID_Emp ,
A.Name,
A.DateTime ,
COALESCE(NULL, 'N/A') AS LastEvent ,
COALESCE(NULL, 'N/A') AS NextEvent
FROM Level1 A
LEFT JOIN Level1 LastVal
ON A.ID_Emp = LastVal.ID_Emp
AND A.RowNum - 1 = LastVal.RowNum
LEFT JOIN Level1 NextVal
ON A.ID_Emp = NextVal.ID_Emp
AND A.RowNum + 1 = NextVal.RowNum ),
Level3
AS (-- reapply row numbers to row-eliminated set
SELECT ID_Emp ,
Name,
DateTime ,
LastEvent ,
NextEvent ,
ROW_NUMBER() OVER ( PARTITION BY ID_Emp
ORDER BY DateTime ) AS RowNBr
FROM Level2
),
Level4
AS (-- pair enter and exit rows.
SELECT A.ID_Emp ,
A.Name,
A.DateTime ,
B.DateTime AS ExitDateTime
FROM Level3 A
JOIN Level3 B ON A.ID_Emp = B.ID_Emp
AND A.RowNBr + 1 = B.RowNBr
),
LEVEL5
AS (--Calculate the work session duration
SELECT ID_Emp ,
Name,
DATEDIFF(second, DateTime, ExitDateTime)
AS Seconds ,
DateTime ,
ExitDateTime
FROM Level4
)
SELECT ID_Emp ,
Name,
CAST([DateTime] AS Date) AS [Date],
CONVERT(varchar(5), [DateTime], 108) as [In],
CONVERT(varchar(5), [ExitDateTime], 108) As Out,
RIGHT('0' + CAST(Seconds / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(Seconds % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(Seconds % 3600 % 60 AS VARCHAR(2)), 2)
AS TotalHours
FROM Level5;
<强> Live Demo
输出：
ID_EMP NAME DATE IN OUT TOTALHOURS
11 Jonh 2014-05-14 08:16:00.0000000 13:35:00.0000000 05:19:00
12 Elizabe 2014-05-14 14:06:00.0000000 22:39:00.0000000 08:33:00
13 immy 2014-05-14 08:00:00.0000000 17:12:00.0000000 09:12:00
答案 2 :(得分：1)
某些记录中存在重复：以下是我的查询
SELECT * FROM emp_atten
WITH Level1
AS (-- apply row numbers
SELECT empid ,
CAST(DATTIME AS DATETIME) AS [DateTime] ,
ROW_NUMBER() OVER ( PARTITION BY empid
ORDER BY G_DATE ) AS RowNum,attendance
FROM emp_atten
),
LEVEL2
AS (-- find the last and next event type for each row
SELECT A.empid ,
A.DateTime ,
COALESCE(NULL, 'N/A') AS LastEvent ,
COALESCE(NULL, 'N/A') AS NextEvent,
A.attendance
FROM Level1 A
LEFT JOIN Level1 LastVal
ON A.empid = LastVal.empid
AND A.RowNum - 1 = LastVal.RowNum
LEFT JOIN Level1 NextVal
ON A.empid = NextVal.empid
AND A.RowNum + 1 = NextVal.RowNum ),
Level3
AS (-- reapply row numbers to row-eliminated set
SELECT empid ,
DateTime ,
LastEvent ,
NextEvent ,
ROW_NUMBER() OVER ( PARTITION BY empid
ORDER BY DateTime ) AS RowNBr,
attendance
FROM Level2
),
Level4
AS (-- pair enter and exit rows.
SELECT A.empid ,
A.DateTime ,
B.DateTime AS ExitDateTime
FROM Level3 A
JOIN Level3 B ON A.empid = B.empid
AND A.RowNBr + 1 = B.RowNBr AND B.attendance='OUT'
),
LEVEL5
AS (--Calculate the work session duration
SELECT empid ,
DATEDIFF(second, DateTime, ExitDateTime)
AS Seconds ,
DateTime ,
ExitDateTime
FROM Level4
)
SELECT empid ,
CAST([DateTime] AS Date) AS [Date],
CONVERT(varchar(5), [DateTime], 108) as [In],
CONVERT(varchar(5), [ExitDateTime], 108) As Out,
RIGHT('0' + CAST(Seconds / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(Seconds % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(Seconds % 3600 % 60 AS VARCHAR(2)), 2)
AS TotalHours
FROM Level5;
答案 3 :(得分：0)
以下是带有测试数据的Oracle查询：
WITH EMP_tABLE AS
(
SELECT A.*,
RANK() OVER (PARTITION BY IDD ORDER BY DATEE) RANKK
FROM (
SELECT '11' IDD, 'Jonh' NAMEE , TO_DATE('14/05/2014 8:16', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
UNION
SELECT '11' IDD, 'Jonh' NAMEE , TO_DATE('14/05/2014 13:35', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
UNION
SELECT '11' IDD, 'Jonh' NAMEE , TO_DATE('14/05/2014 17:23', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
UNION
SELECT '11' IDD, 'Jonh' NAMEE , TO_DATE('14/05/2014 21:09', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
UNION
SELECT '12' IDD, 'Elizabe' NAMEE , TO_DATE('14/05/2014 14:06', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
UNION
SELECT '12' IDD, 'Elizabe' NAMEE , TO_DATE('14/05/2014 22:39', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
UNION
SELECT '13' IDD, 'Jimmy' NAMEE , TO_DATE('11/05/2014 8:00', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
UNION
SELECT '13' IDD, 'Jimmy' NAMEE , TO_DATE('11/05/2014 17:12', 'DD/MM/YYYY HH24:MI') DATEE FROM DUAL
) A )
SELECT AA.IDD, AA.NAMEE,
TO_CHAR(AA.DATEE, 'DD/MM/YYYY') DATE_ONLY, TO_CHAR(AA.DATEE,'HH24:MI') TIME_IN, TO_CHAR(BB.DATEE,'HH24:MI') TIME_OUT,
TRUNC (MOD ( (BB.DATEE-AA.DATEE)*24*60*60 , (24*60*60)) / (60 * 60)) || ':' ||
TRUNC (MOD ((BB.DATEE-AA.DATEE)*24*60*60, (60*60)) / 60)
DURATION
FROM EMP_TABLE AA, EMP_TABLE BB
WHERE
AA.IDD = BB.IDD and AA.RANKK + 1 = BB.RANKK
and MOD(AA.RANKK , 2) = 1 ;
以下是您使用的查询。
将 MY_TABLE, IDD, NAMEE, DATEE替换为相应的表格/字段名称。
WITH EMP_tABLE AS
(
SELECT my_table.*,
RANK() OVER (PARTITION BY IDD ORDER BY DATEE) RANKK
FROM my_table
)
SELECT AA.IDD, AA.NAMEE,
TO_CHAR(AA.DATEE, 'DD/MM/YYYY') DATE_ONLY, TO_CHAR(AA.DATEE,'HH24:MI') TIME_IN, TO_CHAR(BB.DATEE,'HH24:MI') TIME_OUT,
TRUNC (MOD ( (BB.DATEE-AA.DATEE)*24*60*60 , (24*60*60)) / (60 * 60)) || ':' ||
TRUNC (MOD ((BB.DATEE-AA.DATEE)*24*60*60, (60*60)) / 60)
DURATION
FROM EMP_TABLE AA, EMP_TABLE BB
WHERE
AA.IDD = BB.IDD and AA.RANKK + 1 = BB.RANKK
and MOD(AA.RANKK , 2) = 1