Question

我正在开发一个需要从链接获取网页源的应用程序，然后从该页面解析html。

你能给我一些例子，或者从哪里开始编写这样的应用程序？

Answer 1

您可以使用HttpClient执行HTTP GET并检索HTML响应，如下所示：

HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);

String html = "";
InputStream in = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
    str.append(line);
}
in.close();
html = str.toString();

Answer 2

我建议jsoup。

根据他们的网站：

获取维基百科主页，将其解析为DOM，并从新闻部分中选择元素列表中的标题（在线样本）：

Document doc = Jsoup.connect("http://en.wikipedia.org/").get();
Elements newsHeadlines = doc.select("#mp-itn b a");

入门：

Download jsoup jar核心库
阅读cookbook简介

Answer 3

这个问题有点陈旧，但我想我应该发布我的答案，因为DefaultHttpClient，HttpGet等已被弃用。在给定URL的情况下，此函数应该获取并返回HTML。

public static String getHtml(String url) throws IOException {
    // Build and set timeout values for the request.
    URLConnection connection = (new URL(url)).openConnection();
    connection.setConnectTimeout(5000);
    connection.setReadTimeout(5000);
    connection.connect();

    // Read and store the result line by line then return the entire string.
    InputStream in = connection.getInputStream();
    BufferedReader reader = new BufferedReader(new InputStreamReader(in));
    StringBuilder html = new StringBuilder();
    for (String line; (line = reader.readLine()) != null; ) {
        html.append(line);
    }
    in.close();

    return html.toString();
}

Answer 4

public class RetrieveSiteData extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
    StringBuilder builder = new StringBuilder(100000);

    for (String url : urls) {
        DefaultHttpClient client = new DefaultHttpClient();
        HttpGet httpGet = new HttpGet(url);
        try {
            HttpResponse execute = client.execute(httpGet);
            InputStream content = execute.getEntity().getContent();

            BufferedReader buffer = new BufferedReader(new InputStreamReader(content));
            String s = "";
            while ((s = buffer.readLine()) != null) {
                builder.append(s);
            }

        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    return builder.toString();
}

@Override
protected void onPostExecute(String result) {

}
}

Answer 5

如果你看一下here或here，你会发现你不能直接用android API做到这一点，你需要一个外部的图书馆......

如果您需要外部图书馆，可以在此处选择2。

Answer 6

称之为

new RetrieveFeedTask(new OnTaskFinished()
        {
            @Override
            public void onFeedRetrieved(String feeds)
            {
                //do whatever you want to do with the feeds
            }
        }).execute("http://enterurlhere.com");

<强> RetrieveFeedTask.class

class RetrieveFeedTask extends AsyncTask<String, Void, String>
{
    String HTML_response= "";

    OnTaskFinished onOurTaskFinished;


    public RetrieveFeedTask(OnTaskFinished onTaskFinished)
    {
        onOurTaskFinished = onTaskFinished;
    }
    @Override
    protected void onPreExecute()
    {
        super.onPreExecute();
    }

    @Override
    protected String doInBackground(String... urls)
    {
        try
        {
            URL url = new URL(urls[0]); // enter your url here which to download

            URLConnection conn = url.openConnection();

            // open the stream and put it into BufferedReader
            BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream()));

            String inputLine;

            while ((inputLine = br.readLine()) != null)
            {
                // System.out.println(inputLine);
                HTML_response += inputLine;
            }
            br.close();

            System.out.println("Done");

        }
        catch (MalformedURLException e)
        {
            e.printStackTrace();
        }
        catch (IOException e)
        {
            e.printStackTrace();
        }
        return HTML_response;
    }

    @Override
    protected void onPostExecute(String feed)
    {
        onOurTaskFinished.onFeedRetrieved(feed);
    }
}

<强> OnTaskFinished.java

public interface OnTaskFinished
{
    public void onFeedRetrieved(String feeds);
}

Answer 7

其中一个 SO 的帖子回答帮助了我。这不是逐行阅读;假设html文件之间有一行 null 。作为preRequisite，从项目设置中添加此依赖项“com.koushikdutta.ion：ion：2.2.1”在 AsyncTASK 中实现此代码。如果您希望返回的 -something - 位于UI线程中，请将其传递给相互接口。

Ion.with(getApplicationContext()).
load("https://google.com/hashbrowns")
.asString()
.setCallback(new FutureCallback<String>()
 {
        @Override
        public void onCompleted(Exception e, String result) {
            //int s = result.lastIndexOf("user_id")+9;
            // String st = result.substring(s,s+5);
           // Log.e("USERID",st); //something

        }
    });

Answer 8

public class DownloadTask extends AsyncTask<String, Void, String> {

        @Override
        protected String doInBackground(String... urls) {

            String result = "";
            URL url;
            HttpsURLConnection urlConnection = null;

            try {
                url = new URL(urls[0]);

                urlConnection = (HttpsURLConnection) url.openConnection();

                BufferedReader br = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()));


                String inputLine;

                while ((inputLine = br.readLine()) != null)
                {
                    // System.out.println(inputLine);
                    result += inputLine;
                }
                br.close();
                return result;
            } catch (Exception e) {
                e.printStackTrace();
                return "failed";
            }
        }
    }

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        DownloadTask task = new DownloadTask();

        String result = null;

        try {
            result = task.execute("https://www.example.com").get();
        }catch (Exception e){

            e.printStackTrace();
        }
        Log.i("Result", result);

    }

如何从Android中的HTML链接获取页面的HTML源代码？

8 个答案: