Question

我正在使用Hibernate Search 4.5.1和Spring 4.0.5.RELEASE构建一个应用程序。我试图索引以下类：

@Entity
@Indexed
@Analyzer(impl= org.apache.lucene.analysis.standard.StandardAnalyzer.class)
@Table(name="SONG")
@XmlRootElement(name="song")
public class Song  
{
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "ID", updatable = false, nullable = false)
    private Long id;

    @Field(store = Store.YES)
    @Column(name="NAME",  length=255)
    private String name;

    @Field(store = Store.YES)
    @Column(name="ALBUM",  length=255)
    private String album;

    @Field(store = Store.YES)
    @Column(name="ARTIST",  length=255)
    private String artist;

    @NotNull
    @Column(name="PATH",  length=255)
    private String path;

    @NotNull
    @Column(name="PATH_COVER",  length=255)
    private String cover;

    @NotNull
    @Column(name="LAST_VOTE")
    private Date date;

    @Field(store = Store.YES)
    @NotNull
    @Column(name="N_VOTES")
    private int nvotes;

    @NotNull
    @Column(name="ACTIVE", nullable=false, columnDefinition="TINYINT(1) default 0")
    private boolean active;

    @OneToOne(fetch=FetchType.LAZY)
    @JoinColumn(name="IMAGE_ID",insertable=true,updatable=true,nullable=false,unique=false)
    private Image image;

    @IndexedEmbedded
    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "PLAYLIST_ID", nullable = false)
    private PlayList playList;

    @OneToMany(mappedBy = "song")
    private Set<UserVotes> userServices = new HashSet<UserVotes>();

我正在构建一个junit测试用例，如下所示：

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = {"classpath:jukebox-servlet-test.xml"})
@Transactional
public class SongDaoTest {

     @Autowired
     public I_PlaceDao placeDao;
     @Autowired
     public I_PlayListDao playListDao;
     @Autowired
     public I_SongDao songDao;

     @Before
     public void prepare() throws Exception 
     {
            Operation operation = sequenceOf(CommonOperations.DISABLE_CONTRAINTS, CommonOperations.DELETE_ALL,CommonOperations.INSERT_SONG_DATA, CommonOperations.ENABLE_CONTRAINTS);
            DbSetup dbSetup = new DbSetup(new DriverManagerDestination("jdbc:mysql://localhost:3306/jukebox", "root", "mpsbart"), operation);
            dbSetup.launch();
            FullTextSession fullTextSession = Search.getFullTextSession(placeDao.getSession());
            fullTextSession.createIndexer().startAndWait();
     }

    @Test
    @Rollback(false)
    public void searchTest()
    {
        PlayList playList = playListDao.read(1l);
        List<Song> songs = songDao.search(playList, "offspring", 1, 10);
        assertEquals(10, songs.size());
    }

搜索方法实现是：

@SuppressWarnings("unchecked")
    public List<Song> search(PlayList playlist, String searchTerm,int page,int limit) 
    {
        FullTextSession fullTextSession = Search.getFullTextSession(getSession());
        QueryBuilder queryBuilder = fullTextSession.getSearchFactory().buildQueryBuilder().forEntity(Song.class).get();
        BooleanQuery luceneQuery = new BooleanQuery();
        luceneQuery.add(queryBuilder.keyword().onFields("name","album","artist").matching("*"+searchTerm+"*").createQuery(), BooleanClause.Occur.MUST); 
        luceneQuery.add(queryBuilder.phrase().onField("playList.place.id").sentence("\""+playlist.getPlace().getId()+"\"").createQuery(), BooleanClause.Occur.MUST);
        luceneQuery.add(queryBuilder.phrase().onField("playList.id").sentence("\""+playlist.getId()+"\"").createQuery(), BooleanClause.Occur.MUST);
        // wrap Lucene query in a javax.persistence.Query
        FullTextQuery query = fullTextSession.createFullTextQuery(luceneQuery, Song.class);
        org.apache.lucene.search.Sort sort = new Sort(new SortField("n_votes",SortField.INT));
        query.setSort(sort);
        List<Song> songs = query.setFirstResult(page*limit).setMaxResults(limit).list();
        return songs;
    }

测试结果失败，找不到任何匹配的对象。当使用luke lucene时，我可以看到有结果，如果我在luke上尝试hibernate生成的查询，它会返回元素。 hibernate生成的查询是：+（名称：metallica album：metallica artist：metallica）+ playList.place.id：＆＃34; 1 ＆＃34; + playList.id：＆＃34; 1＆＃34;

我还注意到，在luke lucene上，一些索引词的长度最多为六个字符，例如，一首歌的艺术家＆＃34; The Offspring＆＃34;并且存储在索引中的术语是＆＃34;＆＃34;和＆＃34; offspr＆＃34;。第一个没问题，但第二个任期不应该是＃34;后代＆＃34;。为什么要截断这个名字？

Answer 1

如果它对任何人有帮助，我可以通过将查询更改为：

来修复它

        FullTextSession fullTextSession = org.hibernate.search.Search.getFullTextSession(getSession());  
    QueryBuilder qb = fullTextSession.getSearchFactory().buildQueryBuilder().forEntity(Song.class).get();  

    if(searchTerm==null || searchTerm.equals(""))
        searchTerm="*";
    else
        searchTerm="*"+searchTerm+"*";
    Query luceneQuery1 = qb.bool()
            .should(qb.keyword().wildcard().onField("name").matching(searchTerm).createQuery())
            .should(qb.keyword().wildcard().onField("album").matching(searchTerm).createQuery())
            .should(qb.keyword().wildcard().onField("artist").matching(searchTerm).createQuery()).createQuery();
    Query luceneQuery2 = qb.bool()
            .must(qb.keyword().wildcard().onField("playList.place.id").matching(playlist.getPlace().getId()).createQuery())
            .must(qb.keyword().wildcard().onField("playList.id").matching(playlist.getId()).createQuery())
            .createQuery();
    BooleanQuery finalLuceneQuery=new BooleanQuery();
    finalLuceneQuery.add(luceneQuery1, BooleanClause.Occur.MUST);
    finalLuceneQuery.add(luceneQuery2, BooleanClause.Occur.MUST);
    FullTextQuery query = fullTextSession.createFullTextQuery(finalLuceneQuery, Song.class);
    org.apache.lucene.search.Sort sort = new Sort(new SortField("nvotes",SortField.INT,true));
    query.setSort(sort);
    List<Song> songs = query.setFirstResult(page*limit).setMaxResults(limit).list();

Answer 2

如果您检查字段值为null或不为null，则必须在类中的索引字段的字段上添加以下行

<强> @Field（指数= Index.YES，分析= Analyze.NO，存储= Store.YES，indexNullAs = Field.DEFAULT_NULL_TOKEN）

搜索字段如果你想要空值那么 booleanQuery.must（qb.keyword（）onField（ “callReminder”）匹配（ “空”）的createQuery（）。）;

如果您不想要空值

booleanQuery.must（qb.keyword（）onField（ “callReminder”）匹配（ “空”）的createQuery（）...）不（）;

参考文件：http://docs.jboss.org/hibernate/search/4.1/reference/en-US/html/search-mapping.html#search-mapping-entity

Hibernate Search不返回结果

2 个答案: