按开始和结束时间汇总计划数据

时间:2010-03-11 08:06:31

标签: sql sql-server sql-server-2005

我有一个棘手的问题让我头疼了一会儿。我有一些数据代表在可变天数内传递“小部件”,分为半小时插槽。

例如(格式化道歉 - 还没有完全掌握它):

Date          Time    NoOfUnits  
01-Mar-2010   00:00   0  
01-Mar-2010   00:30   0  
01-Mar-2010   01:00   0  
.... (following half hour intervals have NoOfUnits = 0)
01-Mar-2010   23:00   10  
01-Mar-2010   23:30   10
02-Mar-2010   00:00   10
.... (following half hour intervals have NoOfUnits = 1)
02-Mar-2010   07:00   10
02-Mar-2010   07:30   0
.... (following half hour intervals have NoOfUnits = 0)
02-Mar-2010   23:30   0

我需要生成一个查询,允许我将这些数据分组到我提供单元的所有不同块中。在上面的示例中,我需要仅识别1个块 - 23:00到07:00,以及该块的单元总和(160)。因此,所需的结果将是StartTime,EndTime,TotalNoOfUnits。

然而,当我们有不同的交付模式时,复杂性就出现了 - 也许我们有一天可以提供24小时的单位。

我需要能够以上面的格式查询数据并识别所有唯一的StartTime,EndTime和TotalNoOfUnits组合,其中NoOfUnits<> 0

再次为格式化和稍微漫无边际的问题道歉。请向我提出任何问题,以澄清事情。

编辑:为了清楚起见,每天发货时数据将始终从00:00到23:30运行,每半小时的时段将始终存在。对于任何给定的数据集,只有每天半小时槽的天数和单位可能会有所不同。

EDIT2:下面是一个脚本,用于填充表格,其中包含2天的日程安排数据。两天的时间表都是一样的。根据我的要求,我希望看到的结果是13:00,00:00,230。正如您将从下面看到的那样,我的SQL技能并不是很好,因此让人头疼!

declare @DayCount int
declare @HalfHourCount int
declare @HH int
declare @CurrentDate datetime
declare @BaseDate datetime
declare @NoOfUnits int

set @HalfHourCount = 48
set @DayCount = 4
set @BaseDate = '1 Jan 1900'

create table #Schedule
(
Date datetime
, Time datetime
, NoOfUnits int
)

while @DayCount > 0
begin
set @CurrentDate = dateadd(dd, @DayCount * -1, CONVERT(VARCHAR(10),GETDATE(),111))
set @HH = @HalfHourCount

while @HH > 0
begin
    if @HH > 24
        set @NoOfUnits = 10
    else
    begin
        if @DayCount = 4 and @HH < 10
            set @NoOfUnits = 10
        else
            set @NoOfUnits = 0
    end

    insert into #Schedule(Date, Time, NoOfUnits)
    values (@CurrentDate, dateadd(mi, @HH / 2.0 * 60, @BaseDate), @NoOfUnits)

    select @HH = @HH - 1
end

set @DayCount = @DayCount - 1
end

预期结果(尽管测试数据应从00:00开始,然后转到23:00而不是00:30到00:00):

StartTime               TotalUnits  EndDate
----------------------- ----------- -----------------------
1900-01-01 00:30:00.000 90          1900-01-01 04:30:00.000
1900-01-01 12:30:00.000 960         1900-01-02 00:00:00.000

2 个答案:

答案 0 :(得分:3)

根据您提供的数据,这应该有效。它几乎可以肯定地被简化:

;WITH dateCTE
AS
(
        SELECT * 
               ,date + [time] dt
        FROM #Schedule
)
,seqCTE
AS
(
        SELECT NoOfUnits
               ,dt
               ,ROW_NUMBER() OVER (ORDER BY dt) AS rn
        FROM dateCTE               
)
,recCTE
AS
(
        SELECT NoOfUnits
               ,dt
               ,1 AS SEQUENCE
               ,rn
        FROM seqCTE
        WHERE rn = 1

        UNION ALL

        SELECT s.NoOfUnits
              ,s.dt
              ,CASE WHEN (s.NoOfUnits      > 0 
                          AND  r.NoOfUnits > 0
                         )
                      OR (s.NoOfUnits      = 0 
                          AND  r.NoOfUnits = 0
                         )
                    THEN r.SEQUENCE
                    ELSE r.SEQUENCE + 1
               END
              ,s.rn
        FROM recCTE AS r
        JOIN seqCTE AS s
        ON   s.rn = r.rn + 1
)
,summaryCTE
AS
(
        SELECT RIGHT(CONVERT(varchar(23),MIN(dt),120),8)  AS startTime
               ,RIGHT(CONVERT(varchar(23),MAX(dt),120),8) AS endTime
               ,SUM(NoOfUnits) AS NoOfUnits
        FROM recCTE
        GROUP BY SEQUENCE
        HAVING SUM(NoOfUnits) != 0
)
SELECT startTime
       ,endTime
       ,SUM(NoOfUnits)
FROM summaryCTE  
group by startTime
         ,endTime  
OPTION (MAXRECURSION 0)

答案 1 :(得分:1)

如果我理解正确,请看一下这个例子。如果您有更多问题,请与我们联系。

DECLARE @Table TABLE(
        DateVal DATETIME,
        NoOfUnits INT
)

INSERT INTO @Table SELECT '01 Mar 2010 00:30', 0

INSERT INTO @Table SELECT '01 Mar 2010 23:00', 10
INSERT INTO @Table SELECT '01 Mar 2010 23:30', 10
INSERT INTO @Table SELECT '02 Mar 2010 00:30', 10

INSERT INTO @Table SELECT '02 Mar 2010 01:00', 0

INSERT INTO @Table SELECT '02 Mar 2010 02:30', 20
INSERT INTO @Table SELECT '02 Mar 2010 03:30', 30
INSERT INTO @Table SELECT '02 Mar 2010 04:30', 40

INSERT INTO @Table SELECT '02 Mar 2010 05:00', 0

SELECT  *
FROM    @Table

;WITH DateValues AS(
        SELECT  t.DateVal,
                t.NoOfUnits,
                MIN(tNext.DateVal) MinDate
        FROM    @Table t LEFT JOIN
                @Table tNext    ON  t.DateVal < tNext.DateVal
                                AND tNext.NoOfUnits = 0
        WHERE   t.NoOfUnits != 0
        GROUP BY t.DateVal,
                t.NoOfUnits
)
, DateRanges AS(
        SELECT  DateVal StartDate,
                NoOfUnits,

            ISNULL((SELECT MAX(DateVal) FROM @Table WHERE DateVal < MinDate), (SELECT MAX(DateVal) FROM @Table)) EndDateEndDate
        FROM    DateValues
)
SELECT  MIN(StartDate) StartDate,
        SUM(NoOfUnits) TotalUnits,
        EndDate
FROM    DateRanges
GROUP BY EndDate

输出继电器

StartDate               TotalUnits  EndDate
----------------------- ----------- -----------------------
2010-03-01 23:00:00.000 30          2010-03-02 00:30:00.000
2010-03-02 02:30:00.000 90          2010-03-02 04:30:00.000