大家好,我有这个代码将数据插入mysql数据库到表radnici
:
try {
$STH = $db->prepare("INSERT INTO radnici (ime_prezime, jmbg, grad, ulica, posta, telefon, uloga, email, user_id) VALUES (:1,:2,:3,:4,:5,:6,:7,:8,:9)");
$STH->bindParam(':1', $_POST['ime']);
$STH->bindParam(':2', $_POST['jmbg']);
$STH->bindParam(':3', $_POST['grad']);
$STH->bindParam(':4', $_POST['ulica']);
$STH->bindParam(':5', $_POST['posta']);
$STH->bindParam(':6', $_POST['telefon']);
$STH->bindParam(':7', $_POST['pozicija']);
$STH->bindParam(':8', $_POST['email']);
$STH->bindParam(':9', $user_id);
//HERE I NEED TO INSERT DATA TO TABLE WORKHOURS BUT CONNECTED WITH JUST ADDEDED ID
//SO here I NEED query something like this // INSERT INTO radnici (ID, ID_radnici, ime_prezime, jmbg,... here ID_radnici is =with ID from table radnici of added data
$STH->execute();
} catch (PDOException $e) {
echo $e->getMessage();
}
echo "<p>Data submitted successfully</p>";
所以现在当我添加这个时,我需要在这个表中添加workhours
数据,但是只用添加的数据与ID连接......
所以在第二个表中我有:ID, ID_radnici (here I must add ID_radnici same value as ID on table radnici), value, user_id
我写这个但是没有工作: UPDATE:
try {
$STH = $db->prepare("INSERT INTO radnici (ime_prezime, jmbg, grad, ulica, posta, telefon, uloga, email, user_id) VALUES (:1,:2,:3,:4,:5,:6,:7,:8,:9)");
$STH->bindParam(':1', $_POST['ime']);
$STH->bindParam(':2', $_POST['jmbg']);
$STH->bindParam(':3', $_POST['grad']);
$STH->bindParam(':4', $_POST['ulica']);
$STH->bindParam(':5', $_POST['posta']);
$STH->bindParam(':6', $_POST['telefon']);
$STH->bindParam(':7', $_POST['pozicija']);
$STH->bindParam(':8', $_POST['email']);
$STH->bindParam(':9', $user_id);
$orderID = $db -> lastInsertId();
$STH1 = $db->prepare("INSERT INTO workhours (ID_radnika) values($orderID)"); // where $value is the value you want to insert...
$STH->execute();
$STH1->execute();
} catch (PDOException $e) {
echo $e->getMessage();
}
echo "<p>Data submitted successfully</p>";
答案 0 :(得分:1)
使用lastInsertId将执行您想要的操作:
$orderID = $db -> lastInsertId();
答案 1 :(得分:0)
使用lastInsertId()
并使用从其返回的值将数据插入到另一个表中。
这样的事情:
int $lastID = $db->lastInsertId();
if ( $lastID ) {
$STH = $db->prepare("INSERT INTO workhours (ID_radnici, value, userid) values($lastID, $value, $user_id)"); // where $value is the value you want to insert...
$STH->execute();
}