Question

我在python中有一个列表字典，我想检查一个矩阵是否已经存在于dicionary中。

C = {0: [matrix([[ 8.87155979,  2.50616085]]), matrix([[ 0.46289077,  8.05592104]])], 
     1: [matrix([[-1.3115368 ,  7.60922069]])], 
     2: [matrix([[ 0.46289077,  8.05592104]]), matrix([[-1.3115368 ,  7.60922069]]), matrix([[ 3.4826805 , -0.73544937]])]}

此输入应返回true：[[ 8.87155979, 2.50616085]] in C 我怎么能这样做？

Answer 1

C= {0: [[[ 8.87155979, 2.50616085]],[[ 0.46289077, 8.05592104]]], 1: [[[-1.3115368 , 7.60922069]]]}

y = [[ 8.87155979,  2.50616085]]
print  any(y in x for x in C.values())# checks the subelements of the values in your dict
True

根据您的示例，这适用于您的矩阵。

y=[[ 0.46289077,  8.05592104]]

C = {0: [matrix([[ 8.87155979,  2.50616085]]), matrix([[ 0.46289077,  8.05592104]])],
     1: [matrix([[-1.3115368 ,  7.60922069]])],
     2: [matrix([[ 0.46289077,  8.05592104]]), matrix([[-1.3115368 ,  7.60922069]]), matrix([[ 3.4826805 , -0.73544937]])]}



 print any((y == x[0]).all() for x in C.values())
 True

Answer 2

[[ 8.87155979, 2.50616085]] in [m.tolist() for lst in C.values() for m in lst]
True

Answer 3

您可以使用两种不同的方式制作它：有和没有列表理解。 with 是＆＃34; python方式＆＃34;，但这取决于您的决定：

from numpy import *

C = {0: [matrix([[ 8.87155979,  2.50616085]]), matrix([[ 0.46289077,  8.05592104]])], 
     1: [matrix([[-1.3115368 ,  7.60922069]])], 
     2: [matrix([[ 0.46289077,  8.05592104]]), matrix([[-1.3115368 ,  7.60922069]]), matrix([[ 3.4826805 , -0.73544937]])]}

y = [[ 8.87155979, 2.50616085]]

# without list comprehension
for x in C.values():
    for m in x:
        if all(m==y):
            print(True)

# with list comprehension
print(any([all(m==y) for x in C.values() for m in x]))

Answer 4

这很好用：

query = [[8.87155979, 2.50616085]]
any(query[0] in x[0] for x in C.values())

检查矩阵是否在字典列表中

4 个答案: