Question

我可以使用以下代码为我的适配器供电吗？如果是这样，任何想法，我怎么会有点卡住。如果没有，是否有另一种方法来设置arraylist所以我每页有3个选项，而不必为每个食物制作一个新的类/ arraylist。（如果这是唯一的方法，可能是大量的课程）

我将其设置为这样，因为每个按钮都有不同的时间值，可以将低谷放到下一页。

（例如）如果在上一页上，用户选择项目＆＃34;朝鲜蓟＆＃34;应该使用3个按钮加载一个新的页面，温和，中等和做得好（每个人的煮沸时间也不同）。

   package diederik.lucas.boiltime.data;
import java.util.ArrayList;
import java.util.List;

public class TimeOneData {


    private List<Time> Times = new ArrayList<Time>();
    public List<Time> getTimes() {
        return Times;       
    }

    //Not sure if void is the correct return value here
    public void asparagus() {
        addItem(new Time ("Mildly","6"));
        addItem(new Time ("Medium","8"));
        addItem(new Time ("Well Done","10"));
    }

    //Not sure if void is the correct return value here
    public void artichoke() {
        addItem(new Time ("Mildly","5"));
        addItem(new Time ("Medium","7"));
        addItem(new Time ("Well Done","9"));
    }


    //Not sure if void is the correct return value here
    public void beetroot() {
        addItem(new Time ("Mildly","7"));
        addItem(new Time ("Medium","10"));
        addItem(new Time ("Well Done","13"));
    }

    //Not sure if void is the correct return value here
    public void broadBeans() {
        addItem(new Time ("Mildly","1"));
        addItem(new Time ("Medium","2"));
        addItem(new Time ("Well Done","3"));

    }   //Not sure if void is the correct return value here
    public void broccolli() {
        addItem(new Time ("Mildly","4"));
        addItem(new Time ("Medium","8"));
        addItem(new Time ("Well Done","12"));

    }   //Not sure if void is the correct return value here
    public void cabbage() {
        addItem(new Time ("Mildly","3"));
        addItem(new Time ("Medium","6"));
        addItem(new Time ("Well Done","9"));
    }





    private void addItem(Time item) {
        Times.add(item);
    }


}

上下文：我是一个初学者，正在尝试学习Java + android app构建。如果你能给我一个答案，请尽量记住这一点！ TY！

Answer 1

您应该使用Enum来构建数据。由于枚举是对象they can have attributes and methods，您可以设置一个具有ArrayList of times属性的VegetableTime枚举。

然后你可以使用它，如果你需要一个列表，你可以使用VegetableTime.values（）;

来获取它们

顺便说一句，“温和”＆amp; co也应该是一个枚举（可以在时间类中）。

代码示例，这是一种使用它的两个参数定义什么是CookingTime的方法。

public class CookingTime {

    public enum Preparation {

        MILDLY, MEDIUM, WELL_DONE;
    }

    private int time;
    private Preparation preparation;

    CookingTime(Preparation preparation, int time){

        this.time = time;
        this.preparation = preparation;
    }
}

这是一个蔬菜，内联创建了这个烹饪的正确列表。

public enum Vegetable {

    ASPARGUS(Arrays.asList(new CookingTime(CookingTime.Preparation.MILDLY, 8), new CookingTime(CookingTime.Preparation.WELL_DONE, 15)));

    Vegetable(List<CookingTime> cookingTimes){
        this.cookingTimes = cookingTimes;
    }

    private List<CookingTime> cookingTimes;
}

Answer 2

好的，这就是我想出来的：

Enum:

public enum FoodTimeEnum {

ASPARAGUS ("2",  "3", "4"),
ARTICHOKE ("8",  "12", "16");
//more veggies


private final String mildly;
private final String medium;
private final String welldone;

private FoodTimeEnum(String mildly, String medium, String welldone) {
    this.mildly = mildly;
    this.medium = medium;
    this.welldone = welldone;
}

public String getMildly() {
    return mildly;
}

public String getMeduim() {
    return medium;
}

public String getWelldone(){
    return welldone;
}

}

和时间类

public class Time {
    public String timeName;
    public String timeMildly;
    public String timeMedium;
    public String timeLong;



    public Time(String id, String boilTime, String mildly, String medium, String welldone) { 
        this.timeName = id;
        this.timeMildly = mildly;
        this.timeMedium = medium;
        this.timeLong = welldone;

    }

    @Override
    public String toString() {
        return timeName;
    }

}

我可以使用此列表来提供Arrayadapter吗？

2 个答案: