Question

我是Django和Python的新手。我正在学习使用Django Tutorial的Tango，我想在教程登录表单中添加一些功能。我的问题是，当登录表单在登录后使用下一个参数重定向用户时，我无法显示表单错误。实现这一目标的最佳方法是什么？

forms.py

from django import forms
from rango.models import Page, Category, UserProfile
from django.contrib.auth.models import User

class UserLoginForm(forms.Form):
    username = forms.CharField(help_text="Please enter a username.", required=True)
    password = forms.CharField(widget=forms.PasswordInput(), help_text="Please enter a password.", required=True)
    class Meta:
        model = User
        fields = ('username', 'password')

views.py

from django.template import RequestContext
from django.shortcuts import render_to_response
from rango.models import Category, Page
from rango.forms import CategoryForm, PageForm, UserLoginForm, UserForm, UserProfileForm
from django.contrib.auth import authenticate, login, logout
from django.http import HttpResponseRedirect, HttpResponse
from django.contrib.auth.decorators import login_required

def user_login(request):
    context = RequestContext(request)
    NEXT = ""
    if 'next' in request.GET:
        NEXT = request.GET['next']
    if request.method == 'POST':
        username = request.POST['username']
        password = request.POST['password']
        user = authenticate(username=username, password=password)
        user_login_form=UserLoginForm(request.POST)
        errors=user_login_form.errors
        if user_login_form.is_valid():
            if user:
                if user.is_active:
                    login(request, user)
                    if request.POST['next']:
                        return HttpResponseRedirect(request.POST['next'])
                    else:
                        return HttpResponseRedirect('/rango/')
                else:
                    return HttpResponse("Your Rango account is disabled.")
            else:
                return HttpResponse ("Invalid login")
        else:
            if request.POST['next']:
                return HttpResponseRedirect(request.POST['next'])
            else:
                print errors
    else:
        user_login_form=UserLoginForm()
    return render_to_response('rango/login.html', {'NEXT': NEXT, 'user_login_form': user_login_form}, context)

Answer 1

如果登录成功并且登录不成功，我猜你是否试图将用户重定向到网址，显示表单错误（如果我错了，请纠正我）。此网址位于＆＃39; next＆＃39;参数。

因为如果您遇到表单错误，用户就不会进行身份验证而您也不必重定向，对吧？

def user_login(request):
    context = RequestContext(request)
    errors = None
    if 'next' in request.GET:
        NEXT = request.GET['next']
    if request.method == 'POST':
        username = request.POST['username']
        password = request.POST['password']
        user_login_form = UserLoginForm(request.POST)

        if user_login_form.is_valid():
            user = authenticate(username=username, password=password)

            if user:
                if user.is_active:
                    login(request, user)
                    if request.POST['next']:
                        return HttpResponseRedirect(request.POST['next'])
                    else:
                        return HttpResponseRedirect('/rango/')
                else:
                    return HttpResponse("Your Rango account is disabled.")
            else:
                return HttpResponse("Invalid login")
        else:
            errors = user_login_form.errors
            NEXT = request.POST['next']

    user_login_form=UserLoginForm()
    return render_to_response('rango/login.html', {'NEXT': NEXT, 
                              'user_login_form': user_login_form,
                              'errors': errors}, context)

当errors非空时，让模板显示表单错误。

更多

模板可能类似于

<p>{{ errors }}</p> <form action="/contact/" method="post"> {{ user_login_form.as_p }} <input type="submit" value="Submit" /> </form>

当然，这是一个裸露的骨架。阅读this文章，了解更好地展示表单和表单错误的方法。

Answer 2

重定向，不含 next参数。

def user_login(request):
    ... 
    if form.is_valid():
        return HttpResponseRedirect('/user-profile/')
    else:
        # do something else

以上，/user-profile/是您要在登录后将用户重定向到的页面的url。

Django：使用下一个参数表单错误

2 个答案: