Question

尊重所有人，

我有一个来自api的字符串。现在我想从这个字符串中提取有用的数据。此输出是Json查询的结果。字符串是

{＆＃34; PR＆＃34; {＆＃34; URL＆＃34;：＆＃34; http://www.ididthisfilm.com/lex_tmp2/custom-form/＆＃34;＆＃34;域＆＃34;：＆＃34; http://www.ididthisfilm.com＆＃34;，＆＃34;标题＆＃34;：＆＃34;可持续性词典 - 自定义表格＆＃34;，＆＃34;描述＆＃34;：＆＃34;欢迎来到列表编辑表格＆＃34;，＆＃34;图片＆＃34;：[{＆＃34;网址＆＃34;：＆＃34; http://www.ididthisfilm.com/lex_tmp2/wp-content/uploads/2014/05/Lexicon_logo_new_BETA.png＆＃34;，＆＃34; Alt＆＃34;：＆＃34;可持续性词典＆＃34;，＆＃34;标题＆＃34;：＆＃34;＆＃34;，＆＃34; SourceType＆＃34;：1，＆＃34; Width＆＃34;：0，＆＃34;身高＆＃34;：0，＆＃34; ParsedAspectRatio＆＃34;：0}]，＆＃34;画＆＃34;：[]，＆＃34; AUTHORNAME＆＃34;：空，＆＃34 ; ExtraInfo＆＃34;：空}＆＃34; EM＆＃34;：空}`

如何在不同的变量中获取标题和描述以及url，以便我可以在php中使用它们。

Answer 1

使用内置函数json_decode，您将获得JSON对象。

$str=<<<CODE
{"PR":{"Url":"http://www.ididthisfilm.com/lex_tmp2/custom-form/","Domain":"http://www.ididthisfilm.com","Title":"Lexicon Of Sustainability - Custom Form","Description":"Welcome to THE LIST EDIT FORM","Pictures":[{"Url":"http://www.ididthisfilm.com/lex_tmp2/wp-content/uploads/2014/05/Lexicon_logo_new_BETA.png","Alt":"Lexicon Of Sustainability","Title":"","SourceType":1,"Width":0,"Height":0,"ParsedAspectRatio":0}],"Videos":[],"AuthorName":null,"ExtraInfo":null},"EM":null}  
CODE;

print_r( json_decode($str) );

输出

stdClass Object
(
    [PR] => stdClass Object
        (
            [Url] => http://www.ididthisfilm.com/lex_tmp2/custom-form/
            [Domain] => http://www.ididthisfilm.com
            [Title] => Lexicon Of Sustainability – Custom Form
            [Description] => Welcome to THE LIST EDIT FORM
            [Pictures] => Array
                (
                    [0] => stdClass Object
                        (
                            [Url] => http://www.ididthisfilm.com/lex_tmp2/wp-content/uploads/2014/05/Lexicon_logo_new_BETA.png
                            [Alt] => Lexicon Of Sustainability
                            [Title] => 
                            [SourceType] => 1
                            [Width] => 0
                            [Height] => 0
                            [ParsedAspectRatio] => 0
                        )

                )

            [Videos] => Array
                (
                )

            [AuthorName] => 
            [ExtraInfo] => 
        )

    [EM] => 
)

如果发生任何错误，请尝试以下操作：json_last_error()

如何在php中读取json作为字符串？

1 个答案: