在Ajax中将字符串作为参数传递

时间:2014-06-14 10:35:26

标签: javascript php jquery ajax symfony

很多人似乎在使用ajax传递参数时遇到问题。我查看了很多帖子,但没有一个答案对我有用。

我在Symfony工作。我试图通过ajax传递参数,以便我可以更新表数据,但即使javascript读取我的数据,我似乎无法在我的控制器中接收它。

Javascript功能是:

$('#form-save').click(function(){
    $('#myModal').modal('hide');
    var parent = $(this).parent().parent();
    var target = parent.attr('target');
    var title = $('#title-'+target);
    var id = $('#form-info').attr('row');
    var date = $('#date-'+target);
    var dateTime = new Date(date.text());
    var curr_date = ("0" + dateTime.getDate()).slice(-2);;
    var curr_month = ("0" + (dateTime.getMonth() + 1)).slice(-2);
    var curr_year = dateTime.getFullYear();
    var from = $('#from-'+target);
    var till = $('#till-'+target);
    var description = $('#description-'+target);
    //First Log
    console.log(target + title.text() + date.text() + from.text() + till.text() +description.text() );

    $.ajax({
        type: "POST",
        url: "{{ path('restaurant_my_events') }}",
        data: {
            action: 'update',
            id: id,
            title: title.text(),
            date: curr_year + "-" + curr_month + "-" + curr_date ,
            from: from.text(),
            till: till.text(),
            description: description.text()
        },
        dataType: "json",
        success: function(response) {
            //Second Log
            console.log( response );

        }
    });

对于调试我在控制台上记录两次,第一个日志的输出是:

0 hello world   06-14-2014  12:0612:06 description 2 

这确认所有输入元素都匹配,读取数据时没有错误,第二个日志的输出只是为了验证我的控制器是否收到了我的参数。

控制器功能是:

public function myEventsAction(Request $request){
    $restoID = 2;
    $repository = $this->getDoctrine()->getRepository('LesDataBundle:Party');
    $events = $repository->findByRestoId( $restoID );

    if ($request->isXMLHttpRequest()) {
        $status = false;
        $action = $request->get('action');
        $partyID = $request->get('id');
        if($action == 'delete'){
               //Delete function
        }else if($action == 'update'){
                //Update function
        }

        $test = $action ." + ". $partyID ." + ". $request->get('title') ." + " . $request->get('date') ." + " .
            $request->get('from') ." + " . $request->get('till') ." + " . $request->get('description');

        return new JsonResponse(array(
            'id' => $partyID , 'request' => $request , 'test' => $test));
    }


    return $this->render("LesRestaurantBundle:Admin:Events/myEvents.html.twig",
                array( 'events' => $events ));
}

第二次记录的输出是:

Object {id: "2", request: Object, test: "update + 2 +  + NaN-aN-aN +  +  + "}

我只收到参数ID。为什么呢?

1 个答案:

答案 0 :(得分:0)

在通过AJAX发送之前,尝试使用encodeURIComponent()转换字符串。