我想知道是否有办法包含行号(基本上告诉我从数据库查询中获取了多少条记录)。 我有以下SQL查询
SELECT w.widget_id, w.class_id, wg.name classname, wg.label AS classgroup, c.label, c.seq,
g.name AS group, p.name, p.type, CASE WHEN v.value IS NOT NULL THEN v.value WHEN g2p.value IS NOT NULL THEN g2p.value ELSE p.value END AS value
FROM widgets_to_categories w
INNER JOIN widget_classes c ON w.class_id = c.class_id
JOIN classes_to_param_groups t2g ON c.class_id = t2g.class_id
JOIN widget_groups g ON t2g.group_id = g.group_id
JOIN param_groups_to_params g2p ON t2g.group_id = g2p.group_id
JOIN provisioning_params p ON g2p.param_id = p.param_id
INNER JOIN widget_cat_groups wg ON c.class_group_id = wg.class_group_id
LEFT JOIN widget_values v ON(w.widget_id=v.device_id AND p.param_id=v.param_id AND g.name=v.group_name )
WHERE w.widget_id=8 ORDER BY c.class_id ASC
它返回的数据如下:
widget_id | class_id | classname | classgroup | label | seq | group | name | type | value
8 | 1 | toy | group A | test label | 1 | toy | reg | text | af
8 | 1 | toy | group A | test label | 1 | reg2 | fall | text | 25327
8 | 1 | toy | group A | test label | 1 | reg2 | pd | text | dvaa
8 | 1 | toy | group A | test label | 1 | reg2 | ext | text | 28235
8 | 1 | toy | group A | test label | 1 | reg1 | ext | text | 28230
8 | 1 | toy | group A | test label | 1 | toy | meec | text | 094F22DE501
8 | 1 | toy | group A | test label | 1 | toy | mmap | text | 0|
8 | 1 | toy | group A | test label | 1 | reg1 | fna | text | 26014
8 | 1 | toy | group A | test label | 1 | reg1 | fall | text | t-123
8 | 1 | toy | group A | test label | 1 | toy | uen | boolean | false
8 | 1 | toy | group A | test label | 1 | toy | adminpd |
我想知道是否有办法让数据库自动生成并返回另一个只是行标识符的列,如下所示:
id |widget_id | class_id | classname | classgroup | label | seq | group | name | type | value
1 | 8 | 1 | toy | group A | test label | 1 | toy | reg | text | af
2 | 8 | 1 | toy | group A | test label | 1 | reg2 | fall | text | 25327
3 | 8 | 1 | toy | group A | test label | 1 | reg2 | pd | text | dvaa
4 | 8 | 1 | toy | group A | test label | 1 | reg2 | ext | text | 28235
5 | 8 | 1 | toy | group A | test label | 1 | reg1 | ext | text | 28230
6 | 8 | 1 | toy | group A | test label | 1 | toy | meec | text | 094F22DE501
7 | 8 | 1 | toy | group A | test label | 1 | toy | mmap | text | 0|
8 | 8 | 1 | toy | group A | test label | 1 | reg1 | fna | text | 26014
9 | 8 | 1 | toy | group A | test label | 1 | reg1 | fall | text | t-123
10 | 8 | 1 | toy | group A | test label | 1 | toy | uen | boolean | false
11 | 8 | 1 | toy | group A | test label | 1 | toy | adminpd | boolean | false
我想我可以通过选择一个临时表来做到这一点..我还没有弄清楚如何做到的语法...但我也想知道是否还有另一种更简单的方法。 一旦我从数据库中获取数据,拥有此ID字段就可以实现操作。
感谢。
答案 0 :(得分:0)
您可以使用row_number
window function
跟踪每个行号。
像这样:
create table foo
(
id serial,
val text
);
INSERT INTO foo (val)
VALUES ('One'), ('Two'), ('Three');
SELECT f.*, row_number() OVER(ORDER BY val)
FROM foo AS f
ORDER BY val;
这是SQL Fiddle
,显示了这一点:
http://sqlfiddle.com/#!15/0c434/2
其他选项:
您可以使用表单查询来计算结果:
SELECT count(*)
FROM
(
SELECT *
FROM foo
);
或者您可以将行计数作为您正在使用的Postgres
库的一部分。例如,psycopg2
(Python
)和DBI
(Perl
)允许这样做(有一些警告)。您正在使用的库可能提供类似的东西。