Question

我有两个日期选择器，用于选择日期范围。以下是他们的代码：

$("#ContentPlaceHolder1_MySearchBox_txtOutDate").datepicker({
    changeMonth: true,
    numberOfMonths: 1,
    dateFormat: 'dd-M-yy',
    onClose: function (selectedDate) {
      $("#ContentPlaceHolder1_MySearchBox_txtInDate").datepicker("option", "minDate", selectedDate);
      DoPostBack();
    },
    beforeShow: function () {
      setTimeout(function () {
        $('.ui-datepicker').css('z-index', 99999999999999);
      }, 0);
    }
  }).val();
  $("#ContentPlaceHolder1_MySearchBox_txtInDate").datepicker({
    changeMonth: true,
    numberOfMonths: 1,
    dateFormat: 'dd-M-yy',
    onClose: function (selectedDate) {
      $("#ContentPlaceHolder1_MySearchBox_txtOutDate").datepicker("option", "maxDate", selectedDate);
      DoPostBack();
    },
    beforeShow: function () {
      setTimeout(function () {
        $('.ui-datepicker').css('z-index', 99999999999999);
      }, 0);
    }
  }).val();

当不允许InDate低于OutDate时，代码工作正常。但我需要将InDate的最小值设置为OutDate后至少3天。我尝试使用New Date(selectedDate)添加3天，但由于“selectedDate”是dd-MMM-YYYY格式的字符串，因此无法转换为日期。

实现目标的最简单方法是什么？

由于

Answer 1

行。我找到了一个使用以下功能的解决方案：

    function parseDate(input) {
  var parts = input.split('-');
  return new Date(parts[2], MonthNameToNumber(parts[1]) - 1, parts[0]);
}

function MonthNameToNumber(MonthName) { 
  switch(MonthName) {
      case "Jan":
        return 1;
        break;
      case "Feb":
        return 2;
        break;
      case "Mar":
        return 3;
        break;
      case "Apr":
        return 4;
        break;
      case "May":
        return 5;
        break;
      case "Jun":
        return 6;
        break;
      case "Jul":
        return 7;
        break;
      case "Aug":
        return 8;
        break;
      case "Sep":
        return 9;
        break;
      case "Oct":
        return 10;
        break;
      case "Nov":
        return 11;
        break;
      case "Dec":
        return 12;
        break;
      default:
        return 1;
  }
}

然后改变：

$("#ContentPlaceHolder1_MySearchBox_txtInDate").datepicker("option", "minDate", selectedDate);

到

          var OutDate = parseDate(selectedDate);
      OutDate.setDate(OutDate.getDate() + 3);
      $("#<%=txtInDate.ClientID%>").datepicker("option", "minDate", OutDate);

和

$("#ContentPlaceHolder1_MySearchBox_txtOutDate").datepicker("option", "maxDate", selectedDate);

到

          var InDate = parseDate(selectedDate);
      InDate.setDate(InDate.getDate() - 3);
      $("#<%=txtOutDate.ClientID%>").datepicker("option", "maxDate", InDate);

设置jquery ui datepickers之间的最小天数差异

1 个答案: