Question

这是我的查询：

$sql = "SELECT TIMESTAMPDIFF AS diff( DAY, (SELECT date_expire FROM tbl_rec), now())";

$query = mysql_qery($sql);

我需要一个返回，这将是php中的一个数组。

请帮忙。

Answer 1

使用TIMEDIFF获取2次

之间的差异

$query = "select timediff(date_expire, now()) diff 
          from tbl_rec;";
$rs = mysql_query($query);
$row = mysql_fetch_assoc($rs);
echo $row['diff'];

Answer 2

使用以下查询日期差异。

SELECT DATEDIFF(CURDATE(),date_add) as diff FROM `Table_name`;

即仅获得日期差异。因此，对于您的表格，请参阅下面的查询

$sql = "SELECT DATEDIFF(CURDATE(),date_expire) as diff FROM `tbl_rec`;
$query = mysql_query($sql,$connection);

要查看输出，首先在mysql管理员或命令提示符下运行sql查询。

SELECT DATEDIFF(CURDATE(),date_expire) as diff FROM `tbl_rec`;

Answer 3

查询只是：

$sql = "SELECT TIMESTAMPDIFF AS diff( DAY, (SELECT date_expire FROM tbl_rec), now())";

你可以像这样生成数组（假设你使用的是MySQL）：

$time= array();

$result = mysql_query($sql);
while(($row = mysql_fetch_assoc($result))) {
    $time= $row['diff'];
}

日期now（）和MySQL中的表内日期之间的差异

3 个答案: