Question

我的数据如下：

ABCAbbz 
XXZxxz
ZAAAZa
Xaaaab

我需要将它们分成两列：

ABCA   bbz 
XXZ    xxz
AAAZ   a
X      aaaab

我尝试使用COLLATE Latin1_General_BIN LIKE '%[a-z]'，但我不知道如何拆分。

（AAxAx永远不会发生。）

Answer 1

您可以使用PATINDEX()功能执行此操作，并强制它区分大小写：

SELECT
    SUBSTRING(
        t.MyColumn
        ,0
        ,PATINDEX('%[a-z]%', t.MyColumn COLLATE Latin1_General_BIN))
    AS uppercase
    ,SUBSTRING(
        t.MyColumn
        ,PATINDEX('%[a-z]%', t.MyColumn COLLATE Latin1_General_BIN)
        ,LEN(t.MyColumn))
    AS lowercase
FROM MyTable t

SQL Fiddle Demo

Answer 2

试试这个：

http://sqlfiddle.com/#!3/4b857a/7

SELECT
LEFT(ColumnA, PATINDEX('%[abcdefghijklmnopqrstuvwxyz]%'
COLLATE Latin1_General_CS_AS,ColumnA)-1),
SUBSTRING(ColumnA, PATINDEX('%[abcdefghijklmnopqrstuvwxyz]%'
COLLATE Latin1_General_CS_AS,ColumnA),LEN(ColumnA))
FROM Table1

Answer 3

with t as (
select 'ZXXabc' as ColumnToScrub
union
select 'Abdsfsdf'
union
select 'YYYSKHFDSbc')

select 
distinct
    ColumnToScrub,
    left(
        ColumnToScrub,
        max(
            case 
                when ASCII( substring( ColumnToScrub , P.number , 1 ) ) between 65 and 90 then P.number 
                else 0 
            end
        ) over (partition by ColumnToScrub)  
    ) as UpperString,
    right(
        ColumnToScrub,
        len(columnToScrub) - 
        max( 
            case 
                when ASCII( substring( ColumnToScrub , P.number , 1 ) ) between 65 and 90 then P.number 
                else 0 
            end
        ) over (partition by ColumnToScrub) 
    ) as LowString
from t
left join master..spt_values P
            on P.number between 1 and len(t.ColumnToScrub)
            and type ='P'

如何分割像＃ABC; ABCxxz＆＃39;进入大写＆＃39; ABC＆＃39;和小写＆＃39; xxz＆＃39;？

3 个答案: