I2C EEPROM读/写Cubieboard 2 Arch Linux

时间:2014-06-12 21:01:43

标签: linux archlinux i2c eeprom

我正在尝试使用Arch Linux在Cu​​bieboard 2上通过i2c读取和写入AT24MAC402 EEPROM。我正在使用i2c-dev库和i2c-tools。

数据表: http://www.atmel.com/images/atmel-8807-seeprom-at24mac402-602-datasheet.pdf

我可以成功地将(某种......)写入所选地址,并从该地址开始依次写入许多咬合。问题是:

  1. 选择第一个地址后,无法重新选择要写入的其他地址。
  2. 无法将EEPROM指向我想要读取的位置(通过虚拟写入),因此几乎无法真正控制EEPROM。
  3. 查看数据表(连续几个小时),看起来我对使用i2c-dev库所需的I2C通信没有那么多的控制权。我可以直接将X位或X字节写入EEPROM。

    简而言之,我想知道如何正确读取和写入这个EEPROM。

        char buf[10];
    
        int com_serial;
        int failcount;
    
        int i2c_init(char filename[40], int addr)
            {
            int file;
    
            if ((file = open(filename,O_RDWR)) < 0)
                    {
                    printf("Failed to open the bus.");
                    /* ERROR HANDLING; you can check errno to see what went wrong */
                    com_serial=0;
                    exit(1);
                    }
    
        if (ioctl(file,I2C_SLAVE,addr) < 0)
                    {
                    printf("Failed to acquire bus access and/or talk to slave.\n");
                    /* ERROR HANDLING; you can check errno to see what went wrong */
                    com_serial=0;
                    exit(1);
                    }
            return file;
            }
    
    
        int main (int argc, char *argv[]) { 
    
        char read_buf[16];
        char write_buf[17];
        int i;
    
        int file;
        file=i2c_init("/dev/i2c-1",0x50); //dev,slavei2caddr
        write_buf[0] = 0x00;
        write_buf[1] = 'H';
        write_buf[2] = 'i';
        write_buf[3] = '!';
        write(file, write_buf, 4);
        //Successfully prints "Hi!" to bytes 0x00 -> 0x02
    
        //Setting EEPROM to point to address 0xA0 to start reading (arbitrary address with known values: all 0xFF)
        write_buf[0] = 0xA0;    
        write(file, write_buf, 1);
    
        //Reading 1 byte from EEPROM, even though there is a '2'; 2 bytes would be '3'
        read(file, read_buf, 2);
    
        for (i=1; i<3; i++){
            printf("%X", read_buf[i]);
        }
        //Prints out from address 0x04 to 0x05 instead of 0xA0 to 0xA1
    
        printf("\n");
    
        }
    

1 个答案:

答案 0 :(得分:0)

我使用linux/i2c-dev.h中的函数正确地工作了。

为了测试代码我得到i2cdump生成的输出并作为输入放到i2c-stub-from-dump工具中,它允许你根据芯片的转储在i2c-stub总线上设置一个或多个假的I2C芯片你想模仿。

#include <stdio.h>
#include <fcntl.h>
#include <unistd.h>
#include <linux/i2c-dev.h>

int i2c_init(const char * i2c_device, const int chip_address)
{
    int file;
    if ((file = open(i2c_device, O_RDWR)) < 0) {
        return -1;
    }
    if (ioctl(file, I2C_SLAVE, chip_address) < 0) {
        close(file);
        return -1;
    }
    return file;
}

int i2c_write(int file, const int data_address, const unsigned char * data, size_t size)
{
    return i2c_smbus_write_i2c_block_data(file, data_address, size, data);
}

void i2c_read(int file, const int data_address, unsigned char * data_vector, size_t size)
{
    unsigned char reg = data_address;
    unsigned int i;
    for(i = 0; i < size; ++i, ++reg) {
        data_vector[i] = i2c_smbus_read_byte_data(file, reg);
    }
}

int main(void) {

    char device[] = "/dev/i2c-6";
    int address = 0x50;
    unsigned char buffer_before[30] = {0};
    unsigned char buffer_after[30] = {0};
    unsigned char data[] = "Hello World!"; 

    int file;
    file = i2c_init(device, address);

    if (file > 0) {
        i2c_read(file, 0x00, buffer_before, sizeof(data)); 
        i2c_write(file, 0x00, data, sizeof(data)); 
        i2c_read(file, 0x00, buffer_after, sizeof(data)); 
        close (file);
    }

    printf("data read before write: %s\n", buffer_before);
    printf("data read after write: %s\n", buffer_after);
    return 0;
}