我想从我的json字符串中删除所有键“id”及其值。问题是“id”来自我的json字符串中的许多级别。我正在使用JSONObject。使用JSONObject，我们只能在顶层删除“id”，但我需要从每个级别删除“id”。请帮帮我
json字符串 -
"{
"success": {
"body": {
"id": 5827,
"siteName": "RPX",
"instances": [
{
"instanceId": "i-3a63035e",
"name": "prdae-mst21a (iserver)",
"state": "running",
"publicDnsName": "ec2-54-209-175-118.compute-1.amazonaws.com",
"tags": [
{
"id": 9783,
"key": "ktier",
"value": "da"
},
{
"id": 9782,
"key": "Name",
"value": "prdae-mst21a (iserver)"
},
{
"id": 9781,
"key": "kreg",
"value": "e"
}
],
"sshAccessInfo": {
"id": 9788,
"keyPair": {
"id": 6050,
"keyName": "Kens key",
"status": "UPLOADED",
"defaultUser": "root",
"passPhrase": "imaginea#@!"
},
"userName": "imaginea"
},
"account": {
"id": 5857,
"accountId": "348713271046",
"type": "AWS",
"ownerAlias": "348713271046",
"regionName": "us-east-1"
},
"availabilityZone": "us-east-1a",
"publicIpAddress": "54.209.175.118",
"instanceType": "m2.2xlarge"
},
{
"instanceId": "i-65ad2346",
"name": "prpoe-pap22e cp",
"state": "running",
"publicDnsName": "ec2-54-86-2-65.compute-1.amazonaws.com",
"tags": [
{
"id": 9755,
"key": "kzone",
"value": "e"
},
{
"id": 9754,
"key": "kreg",
"value": "e"
}
],
"sshAccessInfo": {
"id": 9756,
"keyPair": {
"id": 5895,
"keyName": "rpxprod-rightscale",
"status": "UPLOADED",
"defaultUser": "ubuntu",
"passPhrase": "imaginea#@!"
},
"userName": "imaginea"
},
"account": {
"id": 5857,
"accountId": "348713271046",
"type": "AWS",
"ownerAlias": "348713271046",
"regionName": "us-east-1"
},
"availabilityZone": "us-east-1e",
"publicIpAddress": "54.86.2.65",
"instanceType": "m1.large"
} ],
"filters": [
{
"id": 5828,
"accountInfo": {
"id": 5829,
"type": "AWS",
"regionName": "us-east-1"
}
}
],
"loadBalancers": [
{
"id": 5855,
"name": "st-pgpool-cp",
"vpcId": "vpc-865c68ee",
"instanceIds": [
"i-b81511eb"
],
"availabilityZones": [
"us-east-1e"
]
},
{
"id": 5850,
"name": "pr-pgpool-cp",
"vpcId": "vpc-865c68ee",
"instanceIds": [
"i-ed262988"
],
"availabilityZones": [
"us-east-1d"
]
}
{
"id": 5844,
"name": "qa2-api",
"vpcId": "vpc-865c68ee",
"instanceIds": [
"i-63687842"
],
"availabilityZones": [
"us-east-1a"
]
},
{
"id": 5830,
"name": "prod-portal-https-v31",
"vpcId": "vpc-865c68ee",
"instanceIds": [
"i-97509bfa",
"i-660f0408"
],
"availabilityZones": [
"us-east-1e",
"us-east-1d"
]
}
]
}
}
}"
我想从id，body，instances，sshAccessInfo，filters等移除loadBalancer。请提供一个体面的方式对此。
答案 0 :(得分：4)
不是很好，但如果它可以真的动态，那么你可以使用正则表达式和replaceAll()在解析任何内容之前从JSON字符串中删除所需的键值：
json = json.replaceAll("\"" + prop + "\"[ ]*:[^,}\\]]*[,]?", "")
在您的情况下String prop = "id"。
答案 1 :(得分：0)
请测试以下代码段。它应该很好地与你相遇
/**
* @param args
*/
public static void main(String[] args) {
String jsonStr ="{'id':'2839','body':{'id':'22',objs:[{id:1},{id:2}]}}";
try {
JSONObject obj = new JSONObject(jsonStr);
removeJSONField(obj);
System.out.println(obj);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static void removeJSONField(JSONObject obj) throws JSONException{
obj.remove("id");
Iterator<String> it = obj.keys();
while(it.hasNext()){
String key = it.next();
Object childObj = obj.get(key);
if(childObj instanceof JSONArray){
JSONArray arrayChildObjs =((JSONArray)childObj);
int size = arrayChildObjs.length();
for(int i=0;i<size;i++){
removeJSONField(arrayChildObjs.getJSONObject(i));
}
}
if(childObj instanceof JSONObject){
removeJSONField(((JSONObject) childObj));
}
}
}
答案 2 :(得分：0)
第1步是将JSON字符串解析为一组对象。有几个Java的JSON库，它们并不是很难使用。例如，使用javax.json，您将执行以下操作：
StringReader或ByteArrayInputStream。Json.createReader()以获取JSON阅读器。JSONReader.read()或JSONReader.readObject()将字符串解析为一组JSON对象。其他JSON库将遵循类似的过程，尽管它们的特定类名可能不同。
答案 3 :(得分：0)
我的答案与@ frank.zheng相同，只不过我在if语句中检查数组子节点是否为对象，然后再尝试递归到函数中。
public static void removeJSONField(JSONObject obj) throws JSONException{
obj.remove("id");
Iterator<String> it = obj.keys();
while(it.hasNext()){
String key = it.next();
Object childObj = obj.get(key);
if(childObj instanceof JSONArray){
JSONArray arrayChildObjs =((JSONArray)childObj);
int size = arrayChildObjs.length();
for(int i=0;i<size;i++){
if (arrayChildObjs.get(i) instanceof JSONObject){
removeJSONField(arrayChildObjs.getJSONObject(i));
}
}
}
if(childObj instanceof JSONObject){
removeJSONField(((JSONObject) childObj));
}
}
}