Question

有人可以帮我解决这个我想写的问题。

SELECT sku FROM product p where sku
not in(SELECT sku FROM price_adjustment p) and sku 
in (SELECT sku FROM searchable_product s where is_visible = 'T') and sku 
in (SELECT sku FROM channel_pricing c 
where offer_price > 10.00 and offer_price % 2 = 0) limit 5;

这个查询工作正常，但我也想只选择sk_，其中search_prod_id是不同的。我认为这样可行，但事实并非如此：

SELECT sku, search_prod_id FROM product p where sku 
not in(SELECT sku FROM price_adjustment p) and sku 
in (SELECT sku FROM searchable_product s 
where is_visible = 'T') and sku in 
(SELECT sku FROM channel_pricing c 
where offer_price > 10.00 and offer_price % 2 = 0) and sku 
in (SELECT distinct search_prod_id from product p ) limit 5;

当我运行时，我可以看到每个sku的search_prod_id是相同的。

有人可以告诉我我做错了吗？

Answer 1

您可以通过对search_prod_id进行分组来强制SELECT MAX(sku) sku, search_prod_id FROM product p WHERE sku NOT IN(SELECT sku FROM price_adjustment) AND sku IN (SELECT sku FROM searchable_product WHERE is_visible = 'T') AND sku IN (SELECT sku FROM channel_pricing c WHERE offer_price > 10.00 AND offer_price % 2 = 0) GROUP BY search_prod_id LIMIT 5;

sku in (SELECT distinct search_prod_id from product p )

同样在你的查询中你正在检查sku对search_prod_id，每次匹配它只是运气（运气不好IMO）

{{1}}

Answer 2

尝试此查询可能有效，

'SELECT sku FROM product p where search_prod_id in(
SELECT DISTINCT search_prod_id ,sku FROM product p where sku not in(
SELECT sku FROM price_adjustment p) and sku in (
SELECT sku FROM searchable_product s 
where is_visible = 'T') and sku in 
(SELECT sku FROM channel_pricing c 
where offer_price > 10.00 and offer_price % 2 = 0) limit 5;'

Answer 3

不完全确定我的语法是否正确，但是类似的东西。我在最后一个AND子句中使用了GROUPING，只给了只有一个的search_prod_id！

SELECT sku, search_prod_id 
FROM product p 
WHERE sku not in(SELECT sku FROM price_adjustment  p) 
and sku in (SELECT sku FROM searchable_product s where is_visible = 'T' ) 
and sku in (SELECT sku FROM channel_pricing c where offer_price > 10.00 and offer_price % 2 = 0) 
and sku in (SELECT search_prod_id from product p GROUP BY search_prod_id HAVING count(*) = 1 ) limit 5;

Answer 4

您的查询存在的问题是，在执行

时

sku in (SELECT distinct search_prod_id from product p )

您要添加的查询sku值等于search_prod_id。我认为您正在寻找的查询是这样的：

SELECT distinct sku, search_prod_id  FROM product p where sku not in(SELECT sku FROM price_adjustment p) and sku in (SELECT sku FROM searchable_product s where is_visible = 'T') and sku in (SELECT sku FROM channel_pricing c where offer_price > 10.00 and offer_price % 2 = 0) limit 5;

Answer 5

在最后一个语句(where .. and sku in (SELECT distinct search_prod_id ...中，您只选择与search_prod_id相等的sku。我想你需要像where ... and search_prod_id in (SELECT distinct search_prod_id from product ...

这样的东西

我认为这应该有效：

SELECT sku, search_prod_id FROM product p where sku 
not in(SELECT sku FROM price_adjustment p) and sku 
in (SELECT sku FROM searchable_product s 
where is_visible = 'T') and sku in 
(SELECT sku FROM channel_pricing c 
where offer_price > 10.00 and offer_price % 2 = 0) and search_prod_id 
in (SELECT distinct search_prod_id from product p ) limit 5;

从SQL查询获取数据，其中另一列是唯一的

5 个答案: