Question

我有这个数组

[
   "code:757786",
   "code:940568",
   "dev:P1e655f7431fce787",
   "dev:P06b19c6891673644_fe1d",
   "code:835130",
   "code:716967",
   "dev:P9b6fb5f078267bc6_fdb5",
   "dev:P0a951f6ab1ca70a4_fe58",
   "code:048889",
]

我希望根据＆＃34;分开：＆＃34;所以代码是一个数组而dev是另一个到目前为止我有这个

              var dev = [];
              var code= [];


              for (var i=0;i<obj.length;i++){
                    var tmp=obj[i].split(':');                                              

                    if (tmp[0]='dev'){
                      dev[i]=tmp[1];
                      console.log(dev[i]);

                      $("#main-content").append(dev[i]);
                    }

现在在控制台日志中显示所有细节

Answer 1

在这一行，您的作业=不是比较==。通过使用单=，您将dev分配给tmp[0]，条件将始终评估为true，从而导致if块始终输入。

if (tmp[0]='dev'){
//        ^ change to double ==

Answer 2

你可以这样做

 var data = [
  "code:757786",
   "code:940568",
   "dev:P1e655f7431fce787",
   "dev:P06b19c6891673644_fe1d",
   "code:835130",
   "code:716967",
   "dev:P9b6fb5f078267bc6_fdb5",
   "dev:P0a951f6ab1ca70a4_fe58",
   "code:048889",
 ];
 var dev  = [], 
     code = [];

 for (var i = 0; i < data.length; i++) {
    var value = data[i].split(':');
    if (value[0] === 'dev') {
        dev.push(value[1]);
        $("#main-content").append(value[1]);
    } else {
        code.push(value[1]); 
    }
 }

Answer 3

RegExp怎么样？也许还有一些支票

var a =  [ "code:757786", "code:940568", "dev:P1e655f7431fce787",
    "dev:P06b19c6891673644_fe1d", "code:835130", "code:716967", 
    "dev:P9b6fb5f078267bc6_fdb5", "dev:P0a951f6ab1ca70a4_fe58", "code:048889"],

    res = {dev : [], code : []};
for(var i = 0, l = a.length, tmp; i < l; i++){
    tmp = a[i].match(/^(dev|code):(.*)/);

    !!tmp && res[tmp[1]].push(tmp[2]);
}
console.debug(res);

如何基于元素分离数组并存储在不同的数组中

3 个答案: