Question

我是codeigniter的新手，但我有一些问题：我有表单注册，从我的表单获取输入并将其添加到数据库，并在表单注册下显示此数据。我的问题是在我的ajax函数中，因为它返回我的错误和[object Object]，或者它可能在ajax中没有问题....我不知道...... 谢谢你的帮助... 我的观点和脚本是：

<head>
        <title>Welcome</title>
        <link rel="stylesheet" type="text/css" href="<?php echo base_url('assets/css/main.css'); ?>" />
        <script type="text/javascript" src="<?php echo base_url('assets/js/jquery.js'); ?>"></script>

        <script type="text/javascript" src="<?php echo base_url('assets/js/jquery.validate.js'); ?>"></script>
        <script>
        function AjaxFormRequest(result_id,form_id,url) { 
                $.ajax({ 
                    url:     url, //Адрес подгружаемой страницы 
                    type:     "POST", //Тип запроса 
                    dataType: "html", //Тип данных 
                    data: jQuery("#"+form_id).serialize(),  
                    success: function(response) { //Если все нормально 
                    document.getElementById(result_id).innerHTML = response;
                    alert(response);
                }, 
                error: function(response) {
                 console.log(response);


                document.getElementById(result_id).innerHTML = "Error on sending form"+response; 
                } 
             }); 
        }
        </script>
    </head>
    <body>
    <center>
        <div id="header"> 
            <h1>Welcome friend</h1>
        </div>
        <div id="center"> 
            <div id="move">
                <p>Please make your next move</p>
                <button type="button" onclick="show_button('in');">Sign in</button>
                &nbsp;&nbsp;or&nbsp;&nbsp;
                <button type="button" onclick="show_button('up');">Sign up</button>
            </div>
            <div id="sigin">
                <!-- <form id="form" method="post" action="javascript:void(0);" onsubmit="ajax()"> -->
                <form method="post" action="" id="myform">
                    <input maxlength="20" id="email" name="email" placeholder="Email" type="text">
                    <br>    
                    <input maxlength="20" id="password" name="password" placeholder="Password" type="password">
                    <br>
                    <input maxlength="20" id="conf_password" name="conf_password" placeholder="Confirm password" type="password">
                    <br>
                    <button id ="btsignin" type="submit" name="send" class="send" onclick="AjaxFormRequest('result', 'myform', '<? site_url().'/main/send' ?>')">Sign in</button>
                    <button id ="btsignup" type="submit" name="send" class="send" onclick="AjaxFormRequest('result', 'myform', '<? site_url('main/send'); ?>')">Sign up</button>
                </form>
                <!--  </form> -->
                <button id="cancel" onclick="cancel();">Cancel</button>
            </div>
            <div id="result" >
                <? var_dump(site_url().'/main/send');?>


            </div>
        </div>

    </center>

</body>

主要的php是：

<?php

if (!defined('BASEPATH'))
    exit('No direct script access allowed');

class Main extends CI_Controller {

    function __construct() {
        parent::__construct();
    }

    public function index() {
        $this->load->view('index');
    }

    public function send() {

        if (!isset($_POST['email']) or empty($_POST['email'])) {
            $error1 = "Email?<br />";
        }
        else
            $error1 = NULL;

        if (!isset($_POST['password']) or empty($_POST['password'])) {
            $error2 = "Password?<br />";
        }
        else
            $error3 = NULL;

        if (!isset($_POST['conf_password']) or empty($_POST['conf_password'])) {
            $error3 = "Confirm Password?<br />";
        }
        else
            $error4 = NULL;

        if (empty($error1) and empty($error2) and empty($error3)) {
            $password = $_POST['password'];
            $email = $_POST['email'];
            $type = 1;
            $this->load->library('userlib');
            if ($this->userlib->register($email, $password, $type, true)) {
            echo $_POST['email'];
            echo $_POST['password'];
               echo $_POST['conf_password'];
            } else {
                return false;
            }
        } else {
            echo $error1 . $error2 . $error3;
        }
    }

}

Ajax在codeigniter中返回Object对象

0 个答案: