Question

我已将某些字符转换为二进制字符。现在我想将它们转换回原始字符。有谁能告诉我怎么做？

这是我将代码转换为字符的代码。

string = Integer.toBinaryString(c);

其中c是char类型。因此，当我将char 'a'转换为二进制时，我会得到类似这样的内容 - 1101101

Answer 1

使用基数= 2（ for binary ）的Integer.parseInt(String s, int radix)将String转换为int，然后转换int } char，像这样：

int parseInt = Integer.parseInt(your_binary_string, 2);
char c = (char)parseInt;

Answer 2

幸运的是，Java API提供了一种将二进制字节转换回原始字符的相当简单的方法。

String char = (char)Integer.parseInt(string, 2)

字符串是二进制代码的一个字节（8位）。 2表示我们目前处于基数2.为此，您需要以8位部分提供二进制文件的上述代码块。

但是，函数Integer.toBinaryString（c）并不总是以8的块返回。这意味着你需要确保你的原始输出都是8的倍数。

它最终会看起来像这样：

public String encrypt(String message) {
    //Creates array of all the characters in the message we want to convert to binary
    char[] characters = message.toCharArray();
    String returnString = "";
    String preProcessed = "";

    for(int i = 0; i < characters.length; i++) {
        //Converts the character to a binary string
        preProcessed = Integer.toBinaryString((int)characters[i]);
        //Adds enough zeros to the front of the string to make it a byte(length 8 bits)
        String zerosToAdd = "";
        if(preProcessed.length() < 8) {
            for(int j = 0; j < (8 - preProcessed.length()); j++) {
                zerosToAdd += "0";
            }
        }
        returnString += zerosToAdd + preProcessed;
    }

    //Returns a string with a length that is a multiple of 8
    return returnString;
}

//Converts a string message containing only 1s and 0s into ASCII plaintext
public String decrypt(String message) {
    //Check to make sure that the message is all 1s and 0s.
    for(int i = 0; i < message.length(); i++) {
        if(message.charAt(i) != '1' && message.charAt(i) != '0') {
            return null;
        }
    }

    //If the message does not have a length that is a multiple of 8, we can't decrypt it
    if(message.length() % 8 != 0) {
        return null;
    }

    //Splits the string into 8 bit segments with spaces in between
    String returnString = "";
    String decrypt = "";
    for(int i = 0; i < message.length() - 7; i += 8) {
        decrypt += message.substring(i, i + 8) + " ";
    }

    //Creates a string array with bytes that represent each of the characters in the message
    String[] bytes = decrypt.split(" ");
    for(int i = 0; i < bytes.length; i++) {
        /Decrypts each character and adds it to the string to get the original message
        returnString += (char)Integer.parseInt(bytes[i], 2);
    }

    return returnString;
}

Answer 3

我不确定它在android中有效，但你尝试过简单的演员吗？

byte b = 90; //char Z
char c = (char) b;

Answer 4

以下源代码对我有用。

StringBuilder binary;

创建一个类

public String stringToBinary(String str, boolean pad) {
    byte[] bytes = str.getBytes();
    binary = new StringBuilder();
    for (byte b : bytes)
    {
        binary.append(Integer.toBinaryString((int) b));
        if(pad) { binary.append(' '); }
    }
    System.out.println("String to Binary : "+binary);
    return binary.toString();
}

然后，调用 class

stringToBinary("a",true);

输出：

将二进制字符串转换为char

4 个答案: