在下面的代码中,当我尝试将msgStr转换为整数时,app force关闭。谁能告诉我原因?是因为msgStr格式不正确吗? 注意:msg是一个obj通过处理程序。 msgStr是一个数字字符串。
MainActivity代码:
private handleMessage(Message msg){
byte[] byteArr = (byte[])msg.obj;
String msgStr = new String(byteArr,"utf-8");
try{
int val = Integer.parseInt(msgStr);
}catch(Exception e){
e.printStackTrace;
}
蓝牙连接线程:
private class ConnectedThread extends Thread {
private final BluetoothSocket mmSocket;
private final InputStream mmInStream;
private final OutputStream mmOutStream;
public ConnectedThread(BluetoothSocket socket) {
mmSocket = socket;
InputStream tmpIn = null;
OutputStream tmpOut = null;
// Get the input and output streams, using temp objects because
// member streams are final
try {
tmpIn = socket.getInputStream();
tmpOut = socket.getOutputStream();
} catch (IOException e) { }
mmInStream = tmpIn;
mmOutStream = tmpOut;
}
public void run() {
byte[] buffer = new byte[1024]; // buffer store for the stream
int bytes; // bytes returned from read()
// Keep listening to the InputStream until an exception occurs
while (true) {
try {
// Read from the InputStream
bytes = mmInStream.read(buffer);
// Send the obtained bytes to the UI activity
mHandler.obtainMessage(MESSAGE_READ, bytes, -1, buffer)
.sendToTarget();
} catch (IOException e) {
break;
}
}
}
现在有人能说出问题所在吗?另外,如果mmInStream由数字数据组成,那么如何区分和存储字节数组缓冲区中3位数据的2位数据?
答案 0 :(得分:0)
尝试
String msgString = new String(...);
答案 1 :(得分:0)
更改此
String msgStr = String(byteArr);
到
String msgStr = new String(byteArr);
答案 2 :(得分:0)
String s = new String(byteArr);
System.out.println("Output : " + s);
答案 3 :(得分:0)
这是因为您将字节数组转换为字符串,但这不起作用。您需要使用this constructor:
String msgStr = new String(byteArr, "UTF-8");
当然,UTF-8会根据您使用的字符集而有所不同。
答案 4 :(得分:0)
首先通过以下代码将Byte转换为String。
String msg = new String(bytes, "UTF-8");
然后将您的字符串转换为整数,如下所示。
int m = Integer.parseInt(msg);
答案 5 :(得分:0)
尝试直接将邮件转换为String:
String msgStr = (String)msg.obj;
如果这不起作用也尝试不将其转换为Integer
,则可能检索到的String
不是整数。
您也可以直接将Handler消息作为整数发送,而无需转换它:
yourhandlername.obtainMessage(what, arg1, arg2, obj).sendToTarget();
arg1 :是一个整数
arg2 :是一个整数
所以,收到时:
int val = msg.arg1;