Question

朋友我有一个jsp页面，它从mysql表中检索数据并以表格的形式显示它们。我还将显示另一列，其中包含一个按钮，将状态设置为1。我点击状态按钮时需要更新数据库表。

以下是jsp的代码

<form action="Edit" method="post">
<table cellspacing="8">
<tr>
    <td><b>Name</b>
    </td>
    <td><b>Place</b>
    </td>
    <td><b>Gender</b>
    </td>
    <td><b>UserName</b>
    </td>
    <td><b>Password</b>
    </td>
    <td><b>Status</b>
    </td>
    <td></td>
</tr>
<%
ViewService vs = new ViewService();
ResultSet rs = vs.getRecords();
while(rs.next())
{
    %>
    <tr>
    <td><%=rs.getString(2) %></td>
    <td><%=rs.getString(3) %></td>
    <td><%=rs.getString(4) %></td>
    <td><%=rs.getString(5) %></td>
    <td><%=rs.getString(6) %></td>
    <td><%=rs.getString(7) %></td>
    <td></td>
     <td><input type="text" name="userid" value="<%=rs.getString(2) %>"                                        

             style="visibility: hidden;" > <input type="submit" value="Active"></td>
       </tr>
     <%     }
     %>
     </table>
    </form>

我的编辑servlet是

package Admin;
import java.io.IOException;
import java.sql.Connection;
import java.sql.PreparedStatement;
import java.sql.SQLException;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import DBcon.Dbcon;
@WebServlet("/Edit")
public class Edit extends HttpServlet {
private static final long serialVersionUID = 1L;
public Edit() {
    super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response)     

throws ServletException, IOException {

}

protected void doPost(HttpServletRequest request, HttpServletResponse response)  

throws ServletException, IOException {
    Connection con;
    PreparedStatement ps;
    Dbcon db = new Dbcon();
    con = db.getCon();
    int status=1;
    int userid =Integer.parseInt(request.getParameter("userid"));
    try {
        ps=con.prepareStatement("update tbluser set status = ? where userid 

= ?");
        ps.setInt(7,status);
        ps.setInt(1, userid);
        ps.executeUpdate();
        con.close();
    } catch (SQLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    response.sendRedirect("ViewUser.jsp");
}

}

Answer 1

while while循环

将表单标记放在while循环中（＆lt; td＆gt;）而不是＆lt;表＆gt;

....
<td><%=rs.getString(7) %></td>
<td></td>
 <td>
   <form action="Edit" method="post">
       <input type="text" name="userid" value="<%=rs.getString(2) %>" style="visibility: hidden;" > <input type="submit" value="Active">
    </form>
 </td>
   </tr>
 <%     }
 %>
 </table>

或

使用超链接代替表单和按钮

<td>
   <a href="Edit?userd=<%=rs.getString(2) %>"> Activate </a>
<td>

Answer 2

试试这个兄弟我修改了你的代码。

protected void doPost(HttpServletRequest request, HttpServletResponse response)  

throws ServletException, IOException {
    Connection con;
    PreparedStatement ps;
    Dbcon db = new Dbcon();
    con = db.getCon();
    int status=1;
    int userid =Integer.parseInt(request.getParameter("userid"));
    try {
        ps=con.prepareStatement("update tbluser set status = '"+status+"' where userid = '"+userid+"'");
        ps.executeUpdate();
        int updateQuery = ps.executeUpdate();
        con.close();
    } catch (SQLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    response.sendRedirect("ViewUser.jsp");
}

}

更新mySql表基于jsp页面

2 个答案:

while while循环

或