我希望有三个功能可以做到这样:
function getuser1(){
var user = b();
//do some stuff to user
return user;
}
function getuser2(){
var user = asyncfinduser();
//do some different stuff to user
return user;
}
function asyncfinduser(){
userDB.find( { /* some criteria */ }, function (error, user) {
//return found user to functions above
return user;
});
)
以上显然不会起作用,我该如何解决这个问题呢?谢谢
答案 0 :(得分:0)
由于你不能return
synchronously from async callbacks,你需要使用回调:
function getuser1(callback) {
asyncfinduser(function(error, user) {
if (error) return callback(error);
//do some stuff to user
callback(null, user);
});
}
function getuser2(callback) {
asyncfinduser(function(error, user) {
if (error) return callback(error);
//do some different stuff to user
callback(null, user);
});
}
function asyncfinduser(callback) {
userDB.find( { /* some criteria */ }, function (error, user) {
if (error) return callback(error);
//return found user to functions above
callback(null, user);
});
}
但是,您可以应用promise pattern:
var Promise = …; // some library
function getuser1() {
return asyncfinduser().then(function(user) {
//do some stuff to user
return user;
});
}
function getuser2() {
return asyncfinduser().then(function(user) {
//do some different stuff to user
return user;
});
}
function asyncfinduser() {
return new Promise(function(resolve, reject) {
userDB.find( { /* some criteria */ }, function (error, user) {
if (error) reject(error);
else resolve(user); //return found user to functions above
});
}