我在Objective C中有一个应用程序,我正在转换到Swift。在Objective C中,我有这个方法:
[self.view performSelector:@selector(someSelector) withObject:self afterDelay:0.1f];
我正在使用Swift,但我无法弄清楚如何做到这一点。我试过了:
self.view.performSelector(Selector("someSelector"), withObject: self, afterDelay: 0.1)
以下是我收到的错误:'performSelector' is unavailable: 'performSelector' methods are unavailable
我会用什么电话来调用方法afterDelay
?
更新
这是我最终的结果:
extension NSObject {
func callSelectorAsync(selector: Selector, object: AnyObject?, delay: NSTimeInterval) -> NSTimer {
let timer = NSTimer.scheduledTimerWithTimeInterval(delay, target: self, selector: selector, userInfo: object, repeats: false)
return timer
}
func callSelector(selector: Selector, object: AnyObject?, delay: NSTimeInterval) {
let delay = delay * Double(NSEC_PER_SEC)
let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay))
dispatch_after(time, dispatch_get_main_queue(), {
NSThread.detachNewThreadSelector(selector, toTarget:self, withObject: object)
})
}
}
答案 0 :(得分:149)
Swift 4
DispatchQueue.main.asyncAfter(deadline: .now() + 0.1) {
// your function here
}
Swift 3
DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(0.1)) {
// your function here
}
Swift 2
let dispatchTime: dispatch_time_t = dispatch_time(DISPATCH_TIME_NOW, Int64(0.1 * Double(NSEC_PER_SEC)))
dispatch_after(dispatchTime, dispatch_get_main_queue(), {
// your function here
})
答案 1 :(得分:108)
你可以这样做:
var timer = NSTimer.scheduledTimerWithTimeInterval(0.1, target: self, selector: Selector("someSelector"), userInfo: nil, repeats: false)
func someSelector() {
// Something after a delay
}
let timer = Timer.scheduledTimer(timeInterval: 0.1, target: self, selector: #selector(someSelector), userInfo: nil, repeats: false)
func someSelector() {
// Something after a delay
}
答案 2 :(得分:9)
Swift是静态类型的,因此performSelector:
方法将被淘汰。
相反,使用GCD将合适的块分派给相关队列 - 在这种情况下,它可能是主队列,因为它看起来像你在做UIKit工作。
编辑:the Swift version of the NSRunLoop
documentation(“1个Objective-C符号隐藏”)中也显着缺少相关的performSelector:
,所以你无法直接使用它。有了这个并且它没有出现在Swiftified NSObject
我认为苹果在这里想的很清楚。