Question

我如何在Laravel Model类中编写这样的语句

SELECT * from video where view=(select max(view) from video)

$query = DB::table('video')->select('*');

$alldetails = $query->addSelect('max(view)')->get();

我打算选择具有最大观看次数的视频的所有属性

我的模特

class Video extends Eloquent implements UserInterface, RemindableInterface {
    protected $table = 'video';

    public static function feature(){
        $query = DB::table('video')->select('*');
        $alldetails = $query->addSelect('max(view)')->get();
        return $alldetails;
    }
}

我的控制器

class HomeController extends BaseController {
    public function home(){
        $feature=View::feature();

        return View::make('frontend/index')
        ->with("title","Kromatik Multimedia")
        ->with('feature'.$feature);
    }
}

我的观点

@foreach($feature as $fet)
    $fet->title;
@endforeach

Answer 1

创建一个这样的模型：

class Video extends Eloquent {

    // Laravel expects the table name "videos"
    // for Video model so need to specify here
    // because you didn't follow that convention

    protected $table = 'video';

}

从你的控制器调用这样的东西：

class HomeController extends BaseController {

    public function home()
    {
        // Get the Video model with maximum views; assumed that,
        // view field contains numeric number, i.e. 2 (two views)
        $featured = Video::orderBy('view', 'desc')->first();

        // Load the "index.blade.php" view from "views/frontend" folder
        return View::make('frontend.index')->with('video', $featured);
    }
}

在view中（不需要循环，因为只传递了一个模型）：

{{ $video->title }}
{{ $video->genre }}

如何在Laravel模型类中编写此语句

1 个答案: