Question

我正在尝试编写一个查询，它给出了execoffice_status = 1的记录数（也可以等于= 0）。我想通过使用一个不同的表员工来输出结果名。

我写的查询似乎给了我一些结果，但给了我表中的所有记录甚至在execoffice_status = 0的地方（不知道我将如何将其添加到查询中）。我试图从查询中得到的是execoffice_status = 1的记录数从哪一年（execoffice_date），最终我想从查询中得到的是前十名每年（按年份排序）。

通过下面的查询，我得到所有记录，甚至execoffice_status = 0 查询：

SELECT * 
FROM (
    select      ROW_NUMBER() OVER(PARTITION BY e.emp_namelast order by year(c.execoffice_date) desc ) as RowNum,
                year(c.execoffice_date) as year, e.emp_nameFirst + ' ' +  e.emp_namelast as fullname, count(c.execoffice_status) as stars

    from        phonelist.dbo.employee e 
    join        intranet.dbo.CSEReduxResponses c on c.employee = e.emp_id
    group by    emp_namelast, emp_namefirst, year(c.execoffice_date)

    ) a

order by year

这是我用一些虚拟数据制作的http://sqlfiddle.com/#!3/79f253/1。

Answer 1

对于你问题的第一点，你可以简单地添加一个where子句。

where       c.execoffice_status=1

要获得每年的最高值，Rank可以实现此目的：

SELECT * 
FROM (
    select      RANK() OVER(PARTITION BY year(c.execoffice_date) order by e.emp_namelast desc ) as Rank,
                year(c.execoffice_date) as year, e.emp_nameFirst + ' ' +  e.emp_namelast as lastName, sum(c.execoffice_status) as stars

    from        employee e 
    join        CSEReduxResponses c on c.employeee = e.emp_id
    where       c.execoffice_status=1 
    group by    emp_namelast, emp_namefirst, year(c.execoffice_date)

    ) a
where rank <= 2
order by year

fiddle

按用户的星号对用户进行编号，每年为您提供前2名。（仅适用于10 <= 10）

Answer 2

以下是我理解您的要求的方式。

获取execoffice_status为1的每位员工每年的记录数 execoffice_status可以是一个或零

在这种情况下，你可以使用sum和group by，如果execoffice_status可以是1或0以外的其他数字，那么我们需要使用rownum和count，而不是sum和group by

请告诉我这是否符合您的要求。

select * from(
select a.employeEe,a.execoffice_date, SUM(a.execoffice_status) execoffice_status_count
from CSEReduxResponses a
group by a.employeEe,execoffice_date
  ) a
left outer join employee b
on b.emp_id = a.employeee
where EXECOFFICE_STATUS_COUNT > 0
order by execoffice_date desc;

如果你想得到前10行，我想用sql server你可以选择TOP 10 field1，field2，field3 from table

Answer 3

SELECT * FROM (
select      ROW_NUMBER() OVER(PARTITION BY e.emp_namelast order by year(c.execoffice_date) desc ) as RowNum,
            year(c.execoffice_date) as year, e.emp_nameFirst + ' ' +  e.emp_namelast as lastName, sum(c.execoffice_status) as stars

from        employee e 
join        CSEReduxResponses c on c.employeee = e.emp_id
where       c.execoffice_status <> 0
group by    emp_namelast, emp_namefirst, year(c.execoffice_date)

) a WHERE RowNum<=10  order by year

如何按年份顺序和记录数输出结果？

3 个答案:

fiddle