Question

此函数用于汇总列表的偶数索引中的所有数字，然后将此总和乘以列表的最后一个数字。

checkio = [-37,-36,-19,-99,29,20,3,-7,-64,84,36,62,26,-76,55,-24,84,49,-65,41]




def checkzi(array):
    if len(array) != 0:
        sum_array = 0
        for i in array:
            x = array.index(i)
            if (x % 2 == 0):
                sum_array += int(i)
                print (sum_array)
        print (sum_array)
        answer = (sum_array) * (array[len(array)-1])
        return (answer)
    else:
        return 0


checkzi(checkio)

我得到的'print'输出是： -37 -56 -27 -24 -88 -52 -26 29 -36 -36

通过这个我可以理解，正确添加的最后一个数字是55. 55之后，84没有正确添加。更重要的是，我得到的最终总和是-1476，而假设它是1968年。

我找不到任何理由。不管怎样我都看不到。

任何人都知道吗？

谢谢！

Answer 1

array.index()将始终返回找到值的第一个索引。所以你循环遍历每个元素，然后查看它所在的索引 - 但如果有重复的元素（有），那么你只看到第一个的索引，导致你总是添加（或每当你遇到它时，总是排除那个数字。

更简洁（更快）的方法是首先使用Python的slice notation迭代遍历列表中的偶数元素：

checkio = [-37,-36,-19,-99,29,20,3,-7,-64,84,36,62,26,-76,55,-24,84,49,-65,41]

def checkzi(array):
    sum_array = 0
    for value in array[::2]: #loop over all values at even indexes
        sum_array += value
    return sum_array * array[-1] # multiply by the last element in the original array

使用内置的sum功能，您甚至可以对这一切进行整理：

def checkzi(array):
    return sum(array[::2]) * array[-1]

Answer 2

问题是array.index()将返回值的第一个实例。您的值为84两次 - 因此，由于第一个索引是奇数，因此您永远不会添加它。

您确实需要跟踪索引，而不是依赖于值的唯一性。你这样做

for idx, val in enumerate(array):

现在您的第一个值将是索引，第二个值将是该值。测试idx%2==0，你可以从这里看出来。

更新这里是完整的代码，明确（我希望）这是如何工作的：

checkio = [-37,-36,-19,-99,29,20,3,-7,-64,84,36,62,26,-76,55,-24,84,49,-65,41]

def checkzi(array):
    if len(array) != 0:
        sum_array = 0
        for idx, x in enumerate(array):
            print "testing element", idx, " which has value ", x
            if (idx % 2 == 0):
                sum_array += x
                print "sum is now ", sum_array
            else:
                print "odd element - not summing"
        print (sum_array)
        answer = (sum_array) * (array[len(array)-1])
        return (answer)
    else:
        return 0

checkzi(checkio)

输出：

testing element 0  which has value  -37
sum is now  -37
testing element 1  which has value  -36
odd element - not summing
testing element 2  which has value  -19
sum is now  -56
testing element 3  which has value  -99
odd element - not summing
testing element 4  which has value  29
sum is now  -27
testing element 5  which has value  20
odd element - not summing
testing element 6  which has value  3
sum is now  -24
testing element 7  which has value  -7
odd element - not summing
testing element 8  which has value  -64
sum is now  -88
testing element 9  which has value  84
odd element - not summing
testing element 10  which has value  36
sum is now  -52
testing element 11  which has value  62
odd element - not summing
testing element 12  which has value  26
sum is now  -26
testing element 13  which has value  -76
odd element - not summing
testing element 14  which has value  55
sum is now  29
testing element 15  which has value  -24
odd element - not summing
testing element 16  which has value  84
sum is now  113
testing element 17  which has value  49
odd element - not summing
testing element 18  which has value  -65
sum is now  48
testing element 19  which has value  41
odd element - not summing
48

你显然想把print语句拿出来 - 我添加它们来帮助解释程序流程。

计算返回的值不正确

2 个答案: