Question

我在HTML代码中有这个：

"name":"London Street" dsakjhasfsa safksafas "north":"232","south":"12","east":"113","west":"9","curRoom":"110"

"name":"London Street" something asdgas dsakhdask "north":"0","south":"22","east":"131","west":"19","curRoom":"10"

我试过那些有正则表达式的人，但不知怎的，我在某处失败了。

\"name\":\"\A(...)\Z\"*?north\":\"(d+)\",\"south\":\"(\d+)\",east\":\"(\d+)\",west\":\"(\d+)\",curRoom\":\"(\d+)\"

\"name\":\"^(...)$\"*?north\":\"(\d+)\",\"south\":\"(\d+)\",east\":\"(\d+)\",west\":\"(\d+)\",currentRoom\":\"(d+)\"

\"name\":\"(...)+\"*?north\":\"(\d+)\",\"south\":\"(d+)\",east\":\"(d+)\",west\":\"(\d+)\",currentRoom\":\"(\d+)\"

有了这些捕获，我想创建一个这样的字典： {key是当前房间，值[位置0：带有邻居的列表[1,2,3]，位置1 - 房间的名称]}

我只知道如何实现这一目标，通过为每个房间的变量分配变量，如下所示：

list_of_neighbours = []
number_south = re.findall('south\":\"(\d+)\"', url)
list_of_neighbours.append(number_south)
....
list_of_neighbours = [n,s,e,w]
dictionay ={}
for k, v in list_of_neighbours:
        dictionay[k] = str(number_current_room)
        dictionay[k].append(v)

但这不会增加空间并且步骤太多。问题是：它可能是一个较短的版本？以及如何修复正则表达式？谢谢

Answer 1

您正尝试使用正则表达式解析JSON。别。 JSON基本上已经一个字典，只是以标准格式字符串化。

使用json模块：

import json

rooms = json.loads(some_json_string)

Python - Regex捕获多个字段并使用它们构建字典

1 个答案: