Question

我已经获得了一些Javascript警报的代码。我希望我的客户能够输入代码来访问我网站的某个区域。

目前我有一些JS代码，如果用户输入了错误的凭据，则会创建一个警告框，用户选择好，然后无论如何都会进入网站。这不太理想。

如何提供重新创建提示框的循环，直到提供正确的凭据（变量x）。

   window.onload = function launch() {
            var x = "name of credential";
            var person = prompt("The website is under development\nPlease enter your development code:");
            if (person == x) {
                alert("Success!");
                <?php header("Location : index.php");?>
            } 
            else {
                alert("You have entered the wrong credentials please try again!");
                var person = prompt("The Care Socierty website is under development\nPlease enter your development code:");
            }

克里希纳的建议

    window.onload = function launch() {
            var x = "credential";
            var person = prompt("The website is under development\nPlease enter your development code:");
            if (person == x) {
                alert("Success!");
                window.location;
            } 
            else {
                alert("You have entered the wrong credentials please try again!");
                return false;
            }
        }

Answer 1

试试：

if (person == x) {
  alert("Success!");
  window.location = 'index.php';
} // ...

Answer 2

进行循环以迭代代码

试试这个可能会对你有所帮助

window.onload = function () {
  var x = "name of credential";
  var wrong = true;

  while (wrong) {
    var person = prompt("The website is under development\nPlease enter your development code:");
    if (person == x) {
      alert("Success!");
      wrong = false;
      <?php header("Location : index.php");?>
    }
  }
}

Answer 3

如果你需要继续提示你需要做这样的事情。

在此尝试：http://jsbin.com/duroguji/2/edit

$(function () {
  setTimeout(askPermission,1000);
});

function askPermission()
{
  var success = false;
  var x = "HELLO";
  while(!success)
    {
  var person = prompt("The website is under development\nPlease enter your development     code:", "");
  if (person == x) {
    success = true;
    alert("Success!");
  } 
  else {
    alert("You have entered the wrong credentials please try again!");
    setTimeout(askPermission,1000);
  }
  }
}

提示框重新创建自己，直到输入正确的字段

3 个答案: