Question

我有一个允许用户在数据库表中搜索食谱的表单，他们可以键入他们要查找的食谱的名称，也可以键入一些关键字。

我试图找出如何检查记录标题并根据关键字的密度百分比返回它们。所以说用户搜索“糖醋鸡”结果会找到所有的食谱首先匹配所有的单词，然后所有的食谱与3个单词，然后2，然后1.希望有意义:)）

这是我的

$keywords = mysqli_real_escape_string($con,$_POST['recipe-search']);
$search_keywords = str_replace("and", "",$keywords);

//Find The Latest Recipies
$searchTerms = explode(' ', $search_keywords);
$searchTermBits = array();
foreach ($searchTerms as $term) 
{
    $term = trim($term);
    if (!empty($term)) 
    {
        $searchTermBits[] = "title LIKE '%$term%'";
    }
}
$q = "SELECT * FROM tbl_recipes WHERE ".implode(' OR ', $searchTermBits);

检查与每个关键字匹配的标题，但不会找出标题中关键字的密度。任何人都可以帮助我，我很难过！

非常感谢

Answer 1

试试这个：

$keywords = mysqli_real_escape_string($con,$_POST['recipe-search']);
$search_keywords = preg_replace('/\s{1,}(and\s*)*/', ' ', $keywords);;

//Find The Latest Recipies
$searchTerms = explode(' ', $search_keywords);
$likeStr = "`title` LIKE '%" . implode("%' OR `title` LIKE '%", $search_terms) . "%'";

$q = "SELECT *,(SELECT COUNT(*) FROM `tbl_recipes` WHERE ". $likeStr ." GROUP BY `title`) as `count` FROM `tbl_recipes` WHERE ". $likeStr .") ORDER BY `count` DESC;";

php mysql查询根据匹配的关键字密度返回结果

1 个答案: