Question

在我的项目中，我通过URL传递参数，如

http://site.org/project/controllername/function?id=1&type=free

我想要的是将网址更改为

http://site.org/project/controllername/function/1/free

实际上我正在动态创建URL

<a href="<?php echo base_url()?>controllername/function?id=<?php echo $defaultrow->id;?>&type=free">

控制器代码：

// Inside VideoController
function search()
{
        $userid=$this->tank_auth->get_user_id();    
        $data['userid']=$userid;
        $time=time();
        $data['defaultvideoquery']=$this->db->query("select cv.videotitle,cv.video,cv.thumbnail,
                cv.added_on,cp.description,cv.id,cv.likes,cv.dislikes,cv.views from channel_programmes as cp INNER JOIN channel_videos as cv
                 ON cp.programme_source=cv.id and cp.channel_id=0 and $time>=cp.starttime and $time>=cp.endtime and cp.status=1");

        $data['videonum']=$data['defaultvideoquery']->num_rows();
        $data['page']='video/search';
        $this->load->view('layout/template',$data);
}

// Inside ChannelsController

function playchannel()
{
    if (!$this->tank_auth->is_logged_in()) 
    {       // not logged in
        redirect('auth/login');
    }
    $data['id']=$userid;

    $id=$this->input->get('id');

    if($this->input->get('type'))
    {
        if($this->input->get('type')=="free")
        {
            $time=time();

            $data['currentdate']=$time;

            $pgmquery=$this->db->query("select cp.channel_id,cp.title,cp.programme_source,cp.url,cp.description,cv.status,cv.video,cp.starttime,cp.endtime from
            channel_videos as cv INNER JOIN channel_programmes as cp ON cv.id=cp.programme_source where cp.status=1 and cv.id=$id");
        }
        else
        {
            $query=$this->db->query("select id,title,thumbnail,channel_type,created_on,status,channel_type,description from videochannel
             where created_for=$userid and id=$id");
            $data['queryresult']=$query->row();
            $data['channeldata']=$query->result();
        }

        $data['pgmnum']=$pgmquery->num_rows();
        $data['pgmresult']=$pgmquery->result();
    }
    $data['page']='channels/playchannel';
    $this->load->view('layout/template',$data);
}

查看代码：

if(isset($videonum))
{
    if($videonum>0)
    {
         foreach($defaultvideoquery->result() as $defaultrow)
         {?>
            <a href="<?php echo base_url()?>channels/playchannel?id=<?php echo $defaultrow->id;?>&type=free">
        <?php if($defaultrow->thumbnail=="")
        { ?>
            <img src="<?php echo base_url();?>images/No_image.png" class="videothumb" alt="Video thumbnail <?php echo $defaultrow->videotitle;?>">

      <?php } 
        else
        { ?>
            <img src="<?php echo base_url();?>channel/<?php echo $defaultrow->id;?>/<?php echo $defaultrow->thumbnail;?>" class="videothumb" alt="Video thumbnail <?php echo $defaultrow->videotitle;?>">   
    <?php   } ?>
        </a>
      }
    }
}

Htaccess代码：

RewriteEngine On
RewriteBase /projectname/
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule \.htaccess - [F]
RewriteRule (.*)(css\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(css\/smoothness\/images\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(js\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(js\/user\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(js\/user\/timeslots\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(channel_data\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(images\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(sliders\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(secure\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(userdata\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(channel\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(css\/admin\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(css\/screen\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(css\/skins\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(css\/fonts\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(css\/images\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(css\/smoothness\/)(.*)$ $2$3 [QSA,L]
RewriteRule (.*)(fonts\/)(.*)$ $2$3 [QSA,L]
RewriteCond %{request_uri} !^index\.php
RewriteRule ^(.*)$ index.php?/$1 [QSA,L]

有没有任何方法可以在不使用htaccess的情况下在Codeigniter中执行此操作。我尝试添加

//$route['(:any)'] = 'controllername/function/$1';
$routes['channels/playchannel/(:any)'] = 'channels/playchannel/$1';

application / config / routes.php 文件中的

。但它返回了404 (Page Not Found) Error。

任何人都可以帮助我实现这一目标。提前谢谢。

Answer 1

这不是已内置的吗？

以下模型 - 视图 - 控制器方法中的URL中的段通常表示：   example.com/class/function/ID

第一个段表示应该调用的控制器类。       第二个段表示应该调用的类函数或方法。       第三个和任何其他段表示ID和将传递给控制器的任何变量。

URI类和URL帮助程序包含的函数使您可以轻松处理URI数据。此外，您可以使用URI路由功能重新映射您的URL，以获得更大的灵活性。

来源：http://ellislab.com/codeigniter/user-guide/general/urls.html

您的网址应该是：example.com/Controllername/Functionname/ID/OtherID

在课堂上你会得到这样的ID：

class Controllername
{
   function Functionname($ID = FALSE, $OtherID = FALSE)
   {
       $ID_from_url = $ID;
       $OtherID_from_url = $OtherID;
   }
}

要创建这样的网址，您可以执行多项操作。

$this->load->helper('url');

echo site_url("news/local/123");  // http://example.com/index.php/news/local/123
echo base_url("blog/post/123");  // http://example.com/blog/post/123

基于您的应用程序的新代码：

// function
function playchannel($id = false, $condition = false)
{
if (!$this->tank_auth->is_logged_in()) 
{       // not logged in
    redirect('auth/login');
}
$data['id']=$userid;

if($condition)
{
    if($condition=="free")
    {
        $time=time();

        $data['currentdate']=$time;

        $pgmquery=$this->db->query("select cp.channel_id,cp.title,cp.programme_source,cp.url,cp.description,cv.status,cv.video,cp.starttime,cp.endtime from
        channel_videos as cv INNER JOIN channel_programmes as cp ON cv.id=cp.programme_source where cp.status=1 and cv.id=$id");
    }
    else
    {
        $query=$this->db->query("select id,title,thumbnail,channel_type,created_on,status,channel_type,description from videochannel
         where created_for=$userid and id=$id");
        $data['queryresult']=$query->row();
        $data['channeldata']=$query->result();
    }

    $data['pgmnum']=$pgmquery->num_rows();
    $data['pgmresult']=$pgmquery->result();
}
$data['page']='channels/playchannel';
$this->load->view('layout/template',$data);
}

//view 

if(isset($videonum))
{
if($videonum>0)
{
     foreach($defaultvideoquery->result() as $defaultrow)
     {?>
        <a href="<?php echo base_url()?>channels/playchannel/<?php echo $defaultrow->id;?>/free">
    <?php if($defaultrow->thumbnail=="")
    { ?>
        <img src="<?php echo base_url();?>images/No_image.png" class="videothumb" alt="Video thumbnail <?php echo $defaultrow->videotitle;?>">

  <?php } 
    else
    { ?>
        <img src="<?php echo base_url();?>channel/<?php echo $defaultrow->id;?>/<?php echo $defaultrow->thumbnail;?>" class="videothumb" alt="Video thumbnail <?php echo $defaultrow->videotitle;?>">   
<?php   } ?>
    </a>
  }
}
}

这应该有用。

Answer 2

在Codeigniter中，您可以使用$this->uri->segment(n); // n = 1表示控制器，n = 2表示方法等

这使您可以从URI字符串中检索信息

请考虑此示例http://example.com/index.php/controller/action/1stsegment/2ndsegment

它会返回

$this->uri->segment(1); // controller
$this->uri->segment(2); // action
$this->uri->segment(3); // 1stsegment
$this->uri->segment(4); // 2ndsegment

Answer 3

对于以下链接，您可以使用input-＆gt; post

获取值

http://site.org/project/controllername?id=1&type=free

示例：获取id＆amp;型

//add this in controller function.
$this->input->post('id');

或其他链接http://site.org/project/controllername/function/1/free

通常，对于与'/'分隔的控制器中的每个名称都是URL

的段

$this->uri->segment(n);

<a href="<?php echo site_url();?>controllername/function?id=<?php echo $defaultrow->id;?>&type=free">

了解更多信息visit this link

Answer 4

在CodeIgniter中，您可以通过routes.php。

执行此操作

在你的routes.php中，

$routes['controller/method/param1/param2'] = 'controller/method/$1/$2';

例如，你想要一个像这样的URL：

http://example.com/video/playchannel/13/free

您可以通过您的routes.php重写它：

$routes['video/playchannel/(:any)/(:any)'] = 'video/playchannel/$1/$2';

然后在你的video.php控制器上，

Class Video {
    function __construct() {

    }

    public function playchannel( $id, $type ) {
        // do process
        if (!$this->tank_auth->is_logged_in()) {  
          // not logged in
          redirect('auth/login');
        }
        $data['id'] = $userid;

        if( $type == 'free' ) {
           // do something here
        }
    }
}

因此URL应如下所示：

http://example.com/video/playchannel/13/free

当您未在网址上使用查询字符串时，请勿使用$this->input->get('something')。希望这有帮助！

Codeigniter中的URL参数由斜杠分隔

4 个答案: