Question

我正试图找出一种能够使用$ row和$ row2的方法。我如何将其纳入while语句？

$result=mysql_query("SELECT * FROM infupdates WHERE username='$_SESSION[username]' ORDER BY date DESC");
$result1=mysql_query("SELECT * FROM infupdates WHERE username='test' ORDER BY date DESC");
while ($row1=mysql_fetch_array($result1,MYSQL_ASSOC))
<td><span class="checkmark"><?php if (($row[onetie]==1)) print "✓";?></span></td>
    <td><span class="checkmark"><?php if (($row2[onecro]==1)) print "✓";?></span></td>

Answer 1

最好在查询中使用OR尝试

<?php 
$result=mysql_query("SELECT * FROM infupdates WHERE '".$_SESSION['username']."' OR username='test' ORDER BY date DESC");
while ($row=mysql_fetch_array($result,MYSQL_ASSOC)) {?>
<td><span class="checkmark"><?php if (($row['onetie']==1)) print "✓";?></span></td>
    <td><span class="checkmark"><?php if (($row['onecro']==1)) print "✓";?></span></td>
<?php }?>

同时查看@vutran评论

Answer 2

while（$ row1 = mysql_fetch_array（$ result1，MYSQL_ASSOC）|| $ row = mysql_fetch_array（$ result，MYSQL_ASSOC）） {

}

否则使用＆＃34; UNION＆＃34;在SQL查询

中

Answer 3

您可以使用OR运算符而不是使用两个查询。

<?php $result1=mysql_query("SELECT * FROM infupdates WHERE username='test' OR username=$_SESSION[username] ORDER BY date DESC");
while ($row1=mysql_fetch_array($result1,MYSQL_ASSOC)){ ?>
<td><span class="checkmark"><?php if (($row['onetie']==1)) print "✓";?></span></td>
<td><span class="checkmark"><?php if (($row2['onecro']==1)) print "✓";?></span></td><?php } ?>

$ row = mysql_fetch_array和$ row2 = mysql_fetch_array

3 个答案: