如何清理“一种类型被推断为'任何''警告?

时间:2014-06-10 22:30:48

标签: scala warnings typing

我有以下代码:

class TestActor() extends RootsActor() {

  // Receive is a type resolving to PartialFunction[Any, Unit]
  def rec2 : Actor.Receive = {   
    case "ping" => println("Ping received!!!")
  }

  def recAll = List(super.receive, rec2)

  // Compose parent class' receive behavior with this class' receive
  override def receive = recAll.reduceLeft { (a,b) => a orElse b }
}

运行时此功能正常,但会产生以下警告:

[warn] /Users/me/git/proj/roots/src/multi-jvm/scala/stuff/TestActor.scala:18: a type was inferred to be `Any`; this may indicate a programming error.
[warn]  override def receive = recAll.reduceLeft { (a,b) => a orElse b }
[warn]                                                   ^

如何更改此代码以清除警告?

3 个答案:

答案 0 :(得分:1)

我没有收到代码警告。如果你使用orElse而不减少怎么办?

scala> import akka.actor._
import akka.actor._

scala> class RootActor extends Actor { def receive = { case _ => println("bang") }}
defined class RootActor

scala> class TestActor extends RootActor {
     |   def rec2: Actor.Receive = { case "ping" => println("ping") }
     |   override def receive = super.receive orElse rec2
     | }
defined class TestActor

scala>

答案 1 :(得分:0)

我认为这是因为Akka的默认Actors是无类型的。这意味着您传递的每条消息都是Any类型,而不是模式匹配。所以你要么把类型放在reduceLeft参数中,要么忽略警告。

答案 2 :(得分:0)

Scala 2.11引入了这个新警告