Question

我想在SQL

中对整数的每个字符求和

例如。我有16273481 as INT

但是现在（没有复杂的方法）总和

1 + 6 + 2 + 7 + 3 + 4 + 8 + 1 = 32

Answer 1

DECLARE @someInt INT = 16273481


-- you could put this all into a function
-- and then it would be reusable...
-- 
-- like... SELECT SumOfIndividualIntegers(16273481)

DECLARE @count INT = LEN(@someInt),
        @counter INT = 1

DECLARE @Sum INT = 0

WHILE @counter <= @count
BEGIN
    SELECT @sum += CAST(SUBSTRING(CAST(@someInt AS VARCHAR), @counter, 1) AS int)
    SELECT @counter += 1
END

SELECT @sum --32
-- and then you would RETURN @sum instead

Answer 2

使用余数运算符是否适合您的循环情况？

Pseuodo代码：

x = 16273481; sum = 0;

循环： sum = sum +（x％10）; x =（x / 10）;

这些方面的东西？

SQL数字中每个字符的总和

2 个答案: