Question

我有一个复杂的查询：

 SELECT *
FROM   `relations` L1
WHERE `minor_from` = 2 and `major_from` = 2  and `type` = "friend" 
       AND  EXISTS
  (

       SELECT * FROM   `relations` L2 WHERE  
       (L1.`minor_from` = L2.`minor_to` AND L1.`major_from` = L2.`major_to` and L1.`minor_from` = L2.`minor_to` AND L1.`major_from` = L2.`major_to`) AND 
       (L2.`minor_from` = L1.`minor_to` AND L2.`major_from` = L1.`major_to` and L2.`minor_from` = L1.`minor_to` AND L2.`major_from` = L1.`major_to`)
)

给用户的朋友。

我可以在Bookshelf.js中添加whereRaw但无法添加别名L1 SELECT * FROM relations L1

任何想法如何查询。

编辑：

如果有人可以告诉我如何运行完整的原始查询，将会很有帮助。

Answer 1

将其标记为答案：

我使用knex.js来做到这一点。我可能会并且可能会使用knex方法但是为了测试我有这个：

    knex('relations as L1').where('L1.minor_from', '=',req.body.minor ).where('L1.major_from', '=',req.body.major).where('L1.type', '=', 'friend').whereExists(function() {
                        this.select('*').from('relations as L2').whereRaw(' (L1.`minor_from` = L2.`minor_to` AND L1.`major_from` = L2.`major_to` and L1.`minor_from` = L2.`minor_to` AND L1.`major_from` = L2.`major_to`) AND (L2.`minor_from` = L1.`minor_to` AND L2.`major_from` = L1.`major_to` and L2.`minor_from` = L1.`minor_to` AND L2.`major_from` = L1.`major_to`)');
                }).then(function(collection) { res.json(200, collection);});

如何在Bookshelf.js（别名表）上转换查询

1 个答案: