Question

我们如何得到以下三组的交集？

//A
SELECT 
{} ON 0,
EXISTS(
    [Customer].[Customer].[Customer].MEMBERS
    , {[Product].[Product Categories].[Category].&[1]}
    , "Internet Sales")
 ON 1 
FROM [Adventure Works]

//B
SELECT 
{} ON 0,
EXISTS(
    [Customer].[Customer].[Customer].MEMBERS
    , {[Product].[Product Categories].[Subcategory].&[2]}
    , "Internet Sales")
 ON 1 
FROM [Adventure Works]

//C
SELECT 
{} ON 0,
EXISTS(
    [Customer].[Customer].[Customer].MEMBERS
    , {[Product].[Product Categories].[Product].&[477]}
    , "Internet Sales")
 ON 1 
FROM [Adventure Works]

Product维度中的三个成员是否可以包含一个EXISTS函数？

我可以在三个EXISTS周围嵌套使用嵌套的INTERSECTION，如下所示，但它看起来非常混乱！...

SELECT 
{} ON 0,
INTERSECT(
    EXISTS(
        [Customer].[Customer].[Customer].MEMBERS
        , {[Product].[Product Categories].[Product].&[477]}
        , "Internet Sales"),
    INTERSECT(
            EXISTS(
                [Customer].[Customer].[Customer].MEMBERS
                , {[Product].[Product Categories].[Category].&[1]}
                , "Internet Sales"),
            EXISTS(
                [Customer].[Customer].[Customer].MEMBERS
                , {[Product].[Product Categories].[Subcategory].&[2]}
                , "Internet Sales")
            )
    )
 ON 1 
FROM [Adventure Works]

Answer 1

SELECT 
  {} ON 0
 ,Exists
  (
    Exists
    (
      Exists
      (
        [Customer].[Customer].[Customer].MEMBERS
       ,{[Product].[Product Categories].[Subcategory].&[2]}
       ,"Internet Sales"
      )
     ,{[Product].[Product Categories].[Category].&[1]}
     ,"Internet Sales"
    )
   ,{[Product].[Product Categories].[Product].&[477]}
   ,"Internet Sales"
  ) ON 1
FROM [Adventure Works];

菲利普，

结合三个EXISTS

1 个答案: