Question

当我访问URL API时，我遇到了问题＆＃34;意外的响应代码500＆＃34;

这是我的代码与volley库：

String url= "http://103.241.24.35/android/android_login_api/index.php";

 public void detailURL(String url) {
            Log.v("Android Spinner JSON Data Activity", url);
             queue = Volley.newRequestQueue(this);
            StringRequest sr = new StringRequest(Request.Method.POST,url, new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    ProgressLoadStartLogin.setVisibility(View.GONE);
                    displaystatis_kontenDetail(response);
                    btn_enable();
                }
            }, new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {

                    if( error instanceof NetworkError) {
                    } else if( error instanceof ServerError) {
                    } else if( error instanceof AuthFailureError) {
                    } else if( error instanceof ParseError) {
                    } else if( error instanceof NoConnectionError) {
                    } else if( error instanceof TimeoutError) {                     
                    }
                    statusKoneksi();
                    btn_enable();
                    ProgressLoadStartLogin.setVisibility(View.GONE);
                }
            }){
                @Override
                protected Map<String,String> getParams(){
                    Map<String,String> params = new HashMap<String, String>();
                    params.put("tag",Variabel.login_tag);
                    params.put("username",user);
                    params.put("password", password);
                    params.put("idgcm",GCMid);
                    return params;
                }

                @Override
                public Map<String, String> getHeaders() throws AuthFailureError {
                    Map<String,String> params = new HashMap<String, String>();
                    params.put("Content-Type","application/x-www-form-urlencoded");
                    return params;
                }
            };
            queue.add(sr);
        }

我已在我的清单上设置了Internet权限。

如果我在浏览器上复制了URL，则会响应，我可以访问但如果我输入了代码，则会收到错误500.

NB ：这是唯一的IP地址，因为这是我的VPS服务器的IP地址，而我还没有设置我的服务器域...

我该如何解决？抱歉我的英文。

Answer 1

这不是你的库问题，浏览器通常忽略标题中的错误500并显示内容，但是凌空剂量不这样做并调用onErrorResponse。我认为这是服务器端应用程序问题，但您可以在onErrorResponse中获取响应。为了说服自己，你可以添加RESTClient mozilla add并发送你的截击请求并查看响应。在标题中，它显示错误500内部服务器错误，但您可以在正文部分中看到响应

Answer 2

以下是此错误的解决方案。首先，您需要扩展Reponse类并修改@Override protected Response parseNetworkResponse(NetworkResponse response) { 像这样：

public class CustomRequest extends Request {
    public CustomRequest(int method, String url, ErrorListener listener) {
        super(method, url, listener);
        // TODO Auto-generated constructor stub
    }

    @Override
    protected Response parseNetworkResponse(NetworkResponse response) {
        System.out.println(response.statusCode);
        try {
            Log.d("custom response", "[raw json]: " + (new String(response.data)));
            Gson gson = new Gson();
            String json = new String(response.data, HttpHeaderParser.parseCharset(response.headers));
            return Response.success(response.data,
                HttpHeaderParser.parseCacheHeaders(response));

        } catch (UnsupportedEncodingException e) {
            return Response.error(new ParseError(e));
        } catch (JsonSyntaxException e) {
            return Response.error(new ParseError(e));
        }
    }

    @Override
    protected void deliverResponse(Object arg0) {
        // TODO Auto-generated method stub
    }
}

//--------------------------------------
//to make  request to server we need to use our custom Request like this :
JsonObjectRequest mJsonObjectRequest = new JsonObjectRequest(
    CustomRequest.Method.POST, url, obj, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject response) {
            ;
            try {
                Toast.makeText(

并在错误监听器中：

@Override
public void onErrorResponse(VolleyError arg0) {
    Log.e("erro;r", "error");

    if(arg0.networkResponse.statusCode==500){
        Log.e("error", "" + new String(arg0.networkResponse.data));
        try {
            JSONObject obj = new JSONObject(new String(arg0.networkResponse.data));
            int codeErreur = obj.getInt("code_erreur");
            if (codeErreur == 501) {
                Drawable warning = (Drawable) MonEntretienApplication.getInstance().getResources().getDrawable(R.drawable.warning_red);
                warning.setBounds(new Rect(0, 0, warning.getIntrinsicWidth(), warning.getIntrinsicHeight()));
                email.setError("",warning);
            }
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

意外的响应代码500 URL API Android应用

2 个答案: