Question

我有一个使用EmptyDataTemplate的ASP.NET GridView。在EmptyDataTemplate内部，我有一些文本框和一个用于插入记录的提交按钮。当我尝试访问代码隐藏文件中的ID时，它们没有显示出来。

我的代码：

<asp:GridView ID="gv" runat="server" AutoGenerateColumns="False" BackColor="White"
        BorderColor="#DEDFDE" BorderStyle="None" BorderWidth="1px" CellPadding="4" ForeColor="Black"
        GridLines="Vertical">
        <AlternatingRowStyle BackColor="White" />
        <Columns>
            <asp:BoundField DataField="BankName" HeaderText="Bank Name" />
            <asp:BoundField DataField="IFSCCode" HeaderText="IFSC Code" />
            <asp:BoundField DataField="MICRCODE" HeaderText="MICR Code" />
            <asp:BoundField DataField="BranchName" HeaderText="Branch Name" />
            <asp:BoundField DataField="Address" HeaderText="Address" />
        </Columns>
        <EmptyDataTemplate>
            <div style="border: 1px solid #ccc; width: auto; margin: 20px 470px;">
                <table border="0" cellpadding="2" cellspacing="0">
                    <tr>
                        <th colspan="3" bgcolor="#1e7c9a" style="color: White">
                            Please Enter Your Bank Details
                        </th>
                    </tr>
                    <tr>
                        <td>
                            Bank Name
                        </td>
                        <td>
                            <asp:TextBox ID="txtBankname" runat="server" Width="180px" />
                        </td>
                        <td>
                            <asp:RequiredFieldValidator ID="RequiredFieldValidator1" ErrorMessage="Required"
                                ForeColor="Red" ControlToValidate="txtBankname" runat="server" Width="120" />
                        </td>
                    </tr>
                    <tr>
                        <td>
                            IFSC Code
                        </td>
                        <td>
                            <asp:TextBox ID="txtIfsccode" runat="server" Width="180px" />
                        </td>
                        <td>
                           <asp:RequiredFieldValidator ID="RequiredFieldValidator2" ErrorMessage="Required"
                                ForeColor="Red" ControlToValidate="txtIfsccode" runat="server" />
                        </td>
                    </tr>
                    <tr>
                        <td>
                            MICR Code
                        </td>
                        <td>
                            <asp:TextBox ID="txtMicrcode" runat="server" Width="180px" />
                        </td>
                        <td>
                            &nbsp;
                        </td>
                    </tr>
                    <tr>
                        <td>
                            Branch Name
                        </td>
                        <td>
                            <asp:TextBox ID="txtBranchName" runat="server" Width="180px" />
                        </td>
                        <td>
                           <asp:RequiredFieldValidator ID="RequiredFieldValidator3" ErrorMessage="Required"
                                Display="Dynamic" ForeColor="Red" ControlToValidate="txtBranchName" runat="server" />
                        </td>
                    </tr>
                    <tr>
                        <td>
                            Address
                        </td>
                        <td>
                            <asp:TextBox ID="txtAddress" runat="server" TextMode="MultiLine" />
                        </td>
                        <td>
                            <asp:RequiredFieldValidator ID="RequiredFieldValidator4" ErrorMessage="Required"
                                ForeColor="Red" ControlToValidate="txtAddress" runat="server" />
                        </td>
                    </tr>
                    <tr>
                        <td>
                        </td>
                        <td>
                            <asp:Button ID="btn" Text="Submit" runat="server" OnClick="InsertDetails"/>
                        </td>
                        <td>
                        </td>
                    </tr>
                </table>
            </div>
        </EmptyDataTemplate>
        <FooterStyle BackColor="#CCCC99" />
        <HeaderStyle BackColor="#1e7c9a" Font-Bold="True" ForeColor="White" />
        <PagerStyle BackColor="#F7F7DE" ForeColor="Black" HorizontalAlign="Right" />
        <RowStyle BackColor="#F7F7DE" />
        <SelectedRowStyle BackColor="#CE5D5A" Font-Bold="True" ForeColor="White" />
        <SortedAscendingCellStyle BackColor="#FBFBF2" />
        <SortedAscendingHeaderStyle BackColor="#848384" />
        <SortedDescendingCellStyle BackColor="#EAEAD3" />
        <SortedDescendingHeaderStyle BackColor="#575357" />
    </asp:GridView>

Answer 1

试试这个

Button Insert_Details = gv.Controls[0].Controls[0].FindControl("btn") as Button ;

您可以看到 EXAMPLE

Answer 2

OP解决方案。

完成如下：

$sql = "INSERT INTO `user_sessions`(`email`, `ip_address`, `location`, `lat`, `lng`, `device_type`, `device_imei`, `login_date`, `login_time`, `active`) VALUES (?,?,?,?,?,?,?,?,?,?);";

                $stmt2 = mysqli_stmt_init($con);

                if(!mysqli_stmt_prepare($stmt2, $sql)){
                    $data['result'] = "SQL error";
                    echo json_encode($data);
                    exit();
                } else {

                    mysqli_stmt_bind_param($stmt2, "sssddsssss", $email, $ip, $city, $lat, $lng, $user_device, $user_device_imei, $user_date, $user_time, "1");

                    mysqli_stmt_execute($stmt2);


                    $data['result'] = "login success";
                    $data['user_id'] = $row['user_id'];
                    echo json_encode($data);
                    exit();
                }

EmptyDataTemplate内的文本框无法访问

2 个答案: