我正在尝试将C#代码中的XML参数传递给SQL Server中的存储过程,但它不起作用。
public static void SaveReceiptTrans(string pSiteCode, string xml)
{
try
{
string DBKey = "sn";
string ConnStr = Encryption.DecryptString(ConfigurationManager.ConnectionStrings[DBKey].ConnectionString);
string CmdStr = "prc_pt_Fac_iu";
SqlParameter[] SqlParams = new SqlParameter[1];
SqlParams[0] = new SqlParameter("@pReceiptsWithFactoryNameCode", SqlDbType.Xml);
SqlParams[0].Direction = ParameterDirection.Input;
SqlParams[0].Value = xml;
int i = SqlHelper.ExecuteNonQuery(ConnStr, CommandType.StoredProcedure, CmdStr, SqlParams);
}
catch (Exception ex)
{
UtilLogging.LogException(ex, "Error From -> ", pSiteCode);
}
}
但是没有通过存储过程对表进行任何操作,就好像没有对存储过程进行调用一样。我已经使用虚拟xml字符串测试了存储过程并且它工作正常但是当从c#代码传递参数时它不起作用。
ALTER PROCEDURE [dbo].[prc_pt_Fac_iu]
(
@pReceiptsWithFactoryNameCode XML
)
BEGIN
SET NOCOUNT ON
BEGIN TRY
DECLARE @MAXTRANSID INT, @MAXMOVEID INT, @ROWCOUNT INT, @NEXTTRANSID INT, @NEXTMOVEID INT
DECLARE @IDOC INT
DECLARE @TEMPCOUNT INT, @INTFLAG INT
SELECT
IDENTITY(INT) AS id,
line.item.value('@site_cde', 'char(8)') AS site_cde,
line.item.value('@po_nbr', 'char(17)') AS po_nbr,
line.item.value('@po_line_nbr', 'smallint') AS po_line_nbr,
line.item.value('@ran', 'int') AS ran,
line.item.value('@factory_name_code', 'int') AS factory_name_code,
NULL AS item_id,
NULL AS qty,
NULL AS cur_loc_id,
NULL AS cur_loc_status,
NULL AS trans_id,
NULL AS [user_id]
INTO
#tmpReceiptsWithFactoryNameCode
FROM
@pReceiptsWithFactoryNameCode.nodes('/POLines/POLine') AS line(item)
SELECT
@MAXTRANSID = COALESCE(MAX(trans_id),0)
FROM
PartsTrack_Receipt_Trans (NOLOCK)
WHERE
trans_id IS NOT NULL
UPDATE rt
SET trans_id = @MAXTRANSID + temp.id,
factory_name_code = temp.factory_name_code
FROM PartsTrack_Receipt_Trans_BKP rt
INNER JOIN #tmpReceiptsWithFactoryNameCode temp ON rt.receipt_ack_nbr = temp.ran
AND rt.po_nbr = temp.po_nbr
AND rt.po_line_nbr = temp.po_line_nbr
END
public static int ExecuteNonQuery(string pConnectionString, CommandType pCommandType, string pCommandText, SqlParameter[] pSqlParameters)
{
SqlConnection lSqlConnection = null;
try
{
lSqlConnection = new SqlConnection(pConnectionString);
SqlCommand lSqlCommand = new SqlCommand();
lSqlCommand.CommandType = pCommandType;
lSqlCommand.Connection = lSqlConnection;
lSqlCommand.CommandText = pCommandText;
lSqlCommand.CommandTimeout = 180;
if (pSqlParameters != null)
{
foreach (SqlParameter lSqlParameter in pSqlParameters)
lSqlCommand.Parameters.Add(lSqlParameter);
}
lSqlConnection.Open();
return lSqlCommand.ExecuteNonQuery();
}
catch (SqlException sqlExp)
{
throw sqlExp;
}
catch (Exception exp)
{
throw exp;
}
finally
{
if (lSqlConnection != null && lSqlConnection.State != ConnectionState.Closed)
lSqlConnection.Close();
}
}
我搜索并发现这是传递xml参数的正确方法。
然后我做错了什么?
由于
编辑:
我发现了这个问题。所有建议的方法都是正确的,但由于xml区分大小写,我发现xml节点中的错误匹配正在传递。
答案 0 :(得分:2)
尝试传递XML值with SqlXml。然后它应该工作。
答案 1 :(得分:0)
您需要将变量xml
作为SqlXml
类的实例传入。您可以执行此操作,如下所示:
SqlParams[0].Value = new SqlXml(new MemoryStream(Encoding.UTF8.GetBytes(xml)));