Question

我想使用SleekXMPP并自动接受发送给我的所有聊天室邀请。我知道xep_0045插件可以检测我何时收到邀请，因为我在调试器中收到通知。我仍然对Python很陌生，任何帮助都会受到赞赏。

到目前为止，我在xep_0045插件中找到了一个名为handle_groupchat_invite的函数。具体来说，这段代码：

def plugin_init(self):
        #...
        self.xmpp.registerHandler(Callback('MUCInvite', MatchXMLMask("<message xmlns='%s'><x xmlns='http://jabber.org/protocol/muc#user'><invite></invite></x></message>" % self.xmpp.default_ns), self.handle_groupchat_invite))

#...

def handle_groupchat_invite(self, inv):
        """ Handle an invite into a muc.
        """
        logging.debug("MUC invite to %s from %s: %s", inv['from'], inv["from"], inv)
        if inv['from'].bare not in self.rooms.keys():
            self.xmpp.event("groupchat_invite", inv)

所以我看到这个方法在工作，因为我在终端日志中看到“MUC邀请...”消息。从那里，我希望我需要使用self.plugin['xep_0045'].joinMUC()加入聊天室的URL（由inv["from"]给出）。但是，我不确定在我的脚本中应该在哪里调用此代码。

再次感谢您的帮助。

更新：我还尝试在add_event_handler函数中使用__init__。具体来说，我的代码是：

def __init__(self, jid, password, room, nick):
    sleekxmpp.ClientXMPP.__init__(self, jid, password)

    self.room = room
    self.nick = nick

    # The session_start event will be triggered when
    # the bot establishes its connection with the server
    # and the XML streams are ready for use. We want to
    # listen for this event so that we we can initialize
    # our roster.
    self.add_event_handler("session_start", self.start)

    # The groupchat_message event is triggered whenever a message
    # stanza is received from any chat room. If you also also
    # register a handler for the 'message' event, MUC messages
    # will be processed by both handlers.
    self.add_event_handler("groupchat_message", self.muc_message)

    # The groupchat_presence event is triggered whenever a
    # presence stanza is received from any chat room, including
    # any presences you send yourself. To limit event handling
    # to a single room, use the events muc::room@server::presence,
    # muc::room@server::got_online, or muc::room@server::got_offline.
    self.add_event_handler("muc::%s::got_online" % self.room,
                           self.muc_online)

    self.add_event_hander("groupchat_invite", self.sent_invite)

从那里，我创建了sent_invite函数，代码在这里：

def sent_invite(self, inv):
    self.plugin['xep_0045'].joinMUC(inv["from"], self.nick, wait=True)

但是，当我这样做时，我收到以下错误：

在 init 中输入第66行文件“muc.py” self.add_event_hander（“groupchat_invite”，self.sent_invite）AttributeError：'MUCBot'对象没有属性'add_event_hander'

然而在xep_0045插件中，我看到了这段代码：self.xmpp.event("groupchat_invite", inv)。根据事件处理程序SleekXMPP wiki page，

只要从XML流接收到特定节，就会出现流事件。只要调用 xmpp.event（name，data）（其中xmpp是一个SleekXMPP对象），就会创建触发事件。

有人可以解释我收到错误的原因吗？我也尝试过使用

self.add_event_hander("muc::groupchat_invite", self.sent_invite)

但也没有成功。

Answer 1

我刚刚从git下载了SleekXMPP并添加groupchat_invite这样的处理程序，它可以工作：

diff --git a/examples/muc.py b/examples/muc.py
index 5b5c764..e327fac 100755
--- a/examples/muc.py
+++ b/examples/muc.py
@@ -61,7 +61,10 @@ class MUCBot(sleekxmpp.ClientXMPP):
         # muc::room@server::got_online, or muc::room@server::got_offline.
         self.add_event_handler("muc::%s::got_online" % self.room,
                                self.muc_online)
-
+        self.add_event_handler("groupchat_invite", self.accept_invite)
+
+    def accept_invite(self, inv):
+       print("Invite from %s to %s" %(inv["from"], inv["to"]))

     def start(self, event):
         """

SleekXMPP自动接受所有聊天室邀请

1 个答案: